Yes.astru025 said:So would I take 200 g x 6.5 degrees celsius x 1 cal/ g C ? I come up with 1300 cal, would this be the heat gained by the water?
astru025 said:Once I know the heat gained by the water how can I find the specific heat of the metal?
What was the change in temperature of the metal?astru025 said:Specific heat is measured in cal/ g C. I have 1300 cal. which is the heat that changed the waters temperature and this heat came from the metal. So do I take 1300 cal. / 85 g. x 98 degrees celsius?
astru025 said:I do not know that. Do I use the same equation I used to find change in temp of the water?.
The specific heat capacity of water is 4.186 joules per gram per degree Celsius (J/g°C).
To calculate the heat gained by water, you need to use the formula Q = m x c x ΔT, where Q is the heat gained, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
The temperature of the water will increase because heat is transferred from the hot metal to the water, causing the water molecules to gain energy and vibrate faster, resulting in a higher temperature.
The amount of heat gained by water can be affected by the mass and temperature of the metal, as well as the initial temperature and mass of the water.
Yes, by measuring the change in temperature of the water and using the formula Q = m x c x ΔT, the specific heat capacity of the metal can be calculated. This assumes that the heat lost by the metal is equal to the heat gained by the water.