- #1
caramello
- 14
- 0
Hi,
I have a question regarding on how to determine the impulse response of an LTI system which has the following conditions:
1).its input is x(n) = u(n) and output is y(n) = (1/2)nu(n) ,and
2).x(-1) = -1/3; x(0) = 1; x(1) = 1/2, and x(n) = 0 for all other values of n
My approach:
I know that x(n) can be expressed in terms of the sum from k=-infinity to k=+infinity of x(k)delta(n-k), so:
x(n) = x(-1)delta(n+1) + x(0)delta(n) + x(1)delta(n-1/2) ---> up to here am I right?
then,
I also know that the u(n) in y(n) = (1/2)nu(n) emphasized that h(n)= 0 for n<0
But after that I don't even know how to start in computing the impulse response h(n). I'm so lost here.
can anyone help me with this? thank you soooo much.![Smile :smile: :smile:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
I have a question regarding on how to determine the impulse response of an LTI system which has the following conditions:
1).its input is x(n) = u(n) and output is y(n) = (1/2)nu(n) ,and
2).x(-1) = -1/3; x(0) = 1; x(1) = 1/2, and x(n) = 0 for all other values of n
My approach:
I know that x(n) can be expressed in terms of the sum from k=-infinity to k=+infinity of x(k)delta(n-k), so:
x(n) = x(-1)delta(n+1) + x(0)delta(n) + x(1)delta(n-1/2) ---> up to here am I right?
then,
I also know that the u(n) in y(n) = (1/2)nu(n) emphasized that h(n)= 0 for n<0
But after that I don't even know how to start in computing the impulse response h(n). I'm so lost here.