- #1
alex73
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Ok i have two questions, one i am unsure of and one i don't have a clue how to correctly find it.
You have to work out the inverse function of:
4s/ s^2+4s+8
I think the answer is:
4e^(-2t)*(cos2t+sin2t)
Is this correct?
I have tryed to do this and keep getting it wrong, so could someone please show working of how to do this.
If f(t)=cos2t.u(t) then find the laplace transform for:
3(df/dt)-f(t)
L{cos2t}=s/(s^2+4)
L{3(df/dt)-f(t)}=3(sF(s)-f(0))-F(s)
I think f(0)=1 but not sure
After that i get confused
Thanks
Alex
Homework Statement
You have to work out the inverse function of:
4s/ s^2+4s+8
The Attempt at a Solution
I think the answer is:
4e^(-2t)*(cos2t+sin2t)
Is this correct?
Homework Statement
I have tryed to do this and keep getting it wrong, so could someone please show working of how to do this.
If f(t)=cos2t.u(t) then find the laplace transform for:
3(df/dt)-f(t)
The Attempt at a Solution
L{cos2t}=s/(s^2+4)
L{3(df/dt)-f(t)}=3(sF(s)-f(0))-F(s)
I think f(0)=1 but not sure
After that i get confused
Thanks
Alex