Finding Inverse of Fractions & Intersections

[Aladin]

Q.1: How can we find the inverse of a fraction?
e.g . 1/2-(sqrt)3 .

Q.2: A' intersection (A union U).
what will be the answer?

 

[cristo]

Q.1: How can we find the inverse of a fraction?
e.g . 1/2-(sqrt)3 .

What do you mean by the inverse of a fraction? Do you mean the reciprocal? If so, turn this into an improper fraction and take the reciprocal of that.

Q.2: A' intersection (A union U).
what will be the answer?

What do you think? What are A, A' and U?

 

[symbolipoint]

Q.1: How can we find the inverse of a fraction?
e.g . 1/2-(sqrt)3 .

Q.2: A' intersection (A union U).
what will be the answer?

Q.1: What kind of inverse are you asking? Arithmetic inverse (additive or multiplicative, some other arithmetic kind); or function inverse (which requires a function, not a constant value only)?

Q.2: WHAT?

 

[HallsofIvy]

To add to the questions, does "1/2-(sqrt)3" mean $$\frac{1}{2}-\sqrt{3}$$ or $$\frac{1}{2-\sqrt{3}}$$.
If the former, and if by "inverse" you mean reciprocal, then $$\frac{1}{2}-\sqrt{3}= \frac{1-2\sqrt{3}}{2}$$ and its reciprocal is $$\frac{2}{1-2\sqrt{3}}$$. You can "pretty" that up by rationalizing the denominator.

For the second problem, I'm going to assume that "U" is the universal set and A' is the complement of A.

What is the union of U with any set? What is the intersection of U with any set?

 

[Aladin]

really really sorry Halsof actualy it is
1/(2-sqrt3). I will be thankful to you if you find the inverse of this.

 

[cristo]

really really sorry Halsof actualy it is
1/(2-sqrt3). I will be thankful to you if you find the inverse of this.

Firstly, you should note that we do not give out answers to homework/coursework type questions here. Secondly, you still haven't defined "inverse." Is it the reciprocal you want? If so, what is the reciprocal of a fraction of the form a/(b+c)?

 

[HallsofIvy]

I will echo- what do you mean by "inverse"? The multiplicative inverse (reciprocal)? If so the problem is pretty close to trivial.