- #1
cheerspens
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Homework Statement
The first problem I'm having difficulty with is
[itex]\stackrel{lim}{x\rightarrow0}[/itex] [itex]\frac{sin x}{5x}[/itex]
And the second is:
[itex]\stackrel{lim}{x\rightarrow0}[/itex] [itex]\frac{sin x(1-cos x)}{2x^{2}}[/itex]
Homework Equations
I assume that for the first problem I need to simplify it to the rule where [itex]\stackrel{lim}{x\rightarrow0}[/itex] [itex]\frac{sin x}{x}[/itex]=1
and the second would probably need to simplify to follow the rule [itex]\stackrel{lim}{x\rightarrow0}[/itex] [itex]\frac{1-cos x}{x}[/itex]=0
The Attempt at a Solution
What I mainly need help with is how to get started. For the first problem, how do I get rid of the 5x at the bottom?
For the second problem should I square the entire thing and end up with [itex]\stackrel{lim}{x\rightarrow0}[/itex] [itex]\frac{2sin x}{4x^{4}}[/itex] then go from there or is that even correct?