- #1
k-rod AP 2010
- 36
- 0
Two masses hang from a meterstick whose fulcrum is at 50.0cm. M1=.100kg acts at 20.0 cm, what value of mass m2 at position 70.0 puts the the system at equilibrium?
(.3m*(.1kg*9.8m/s2))=(.2m*(9.8m/s2*x kg))
.294 N*m=.2m(9.8*x N)
1.47 N=9.8*x N
x=.15 kg
Is this procedure correct? The distances in the first equation are from the center of mass, which is y they are different from the distances given in the problem.
(.3m*(.1kg*9.8m/s2))=(.2m*(9.8m/s2*x kg))
.294 N*m=.2m(9.8*x N)
1.47 N=9.8*x N
x=.15 kg
Is this procedure correct? The distances in the first equation are from the center of mass, which is y they are different from the distances given in the problem.