Finding max/min values of challenging function.

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In summary, the conversation discusses finding the maximum and minimum values of two given functions, f(x) and g(x). The first part of the question is completed by finding that both functions reach their extrema at the same value of x, which is 25/ln(1.0001). However, the second part of the question involves finding the actual values of f(x) and g(x) at this critical point. Some suggestions are made, such as using a calculator or transforming f(x) into a Taylor series. The conversation ends with the values of f(x) and g(x) being given as 1.23504x10^124 and 8.0969x10^-125, respectively.
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Homework Statement



I am given two functions:
[tex]f(x)=\frac{x^{25}}{1.0001^x}[/tex]

[tex]g(x)=\frac{1.0001^x}{1.0001^x+x^{25}}[/tex]

I'm first asked to find the values of x for which f(x) reaches a maximum and g(x) reaches the minimum.

Secondly, I'm asked to find the actual max value of f(x) and min value of g(x) to 5 significant digits.

The Attempt at a Solution


I have completed the first part and found that f(x) reaches it's max value and g(x) reaches it's minimum value at the same 'x'. This x value is 25/ln(1.0001).

However, I do not know how to do the second part of the question. Obviously, the x value is incredibly large, since ln(1.0001), it's denominator, is very small. This makes simple calculator use impossible. How then do I calculate the value of f(x) and g(x) at this x?

I have considered of transforming f(x) into a taylor series by expanding x^25. Maybe then I can approximate the function by its taylor series expansion for 5 digits. Is this correct? Furthermore, can I have a hint for evaluating g(x) at its minimum point?


Thank you,
Alex.
 
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  • #2
I just jotted a little bit on a piece of paper; I tried this for f(x): first take the natural log of that function, then later, e^(what it simplifies to). I didn't follow it through to completion, but a couple ln(1.0001)'s canceled out. Later, I ended up with (25/e)^25 * 1/ln(1.0001) (hopefully I don't have a careless error)

Looking at the reciprocal of the ln there, its value is 10000.499991667...
And, the quantity raised to the 25th power isn't so large (written that way) that it makes a calculator useless.
 
  • #3
Do you see a way to write g(x) in terms of f(x)?

Also, the critical point is x=25/ln(1.0001) and f(25/ln(1.0001))=1.23504x10^124 and g(25/ln(1.0001))=8.0969x10^-125.

I used www.quickmath.com[/url] for the calculations, ( the [PLAIN]http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=algebra&s2=simplify&s3=basic will do calculations for you)
 
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  • #4
Yes, I expressed g(x) in terms of f(x). But where does this get me?

I wasn't sure how you managed to calculate those values either. Could it be done with a hand-calculator or does it involve other tools (like quickmath.com)?
 

FAQ: Finding max/min values of challenging function.

How do I determine the maximum or minimum value of a challenging function?

To find the maximum or minimum value of a challenging function, you can use a variety of methods such as finding critical points, using the first or second derivative test, or using optimization techniques. It ultimately depends on the specific function and the information given.

What is a critical point and how does it help me find the maximum or minimum value?

A critical point is a point on the graph of a function where the derivative is equal to 0 or does not exist. This means that the slope of the function is either flat or undefined at that point. By finding the critical points, you can determine potential locations for the maximum or minimum values of the function.

Can I use software or calculators to find the maximum or minimum value of a challenging function?

Yes, there are many software programs and calculators that can help you find the maximum or minimum value of a challenging function. These tools often use algorithms to find the critical points and analyze the behavior of the function to determine the maximum or minimum value.

How do I know if a function has a maximum or minimum value?

A function will have a maximum or minimum value if it is continuous and differentiable on a closed interval. This means that the function must be defined and have a slope at every point within the interval. If these conditions are met, then the function will have at least one maximum or minimum value.

Can a function have more than one maximum or minimum value?

Yes, a function can have multiple maximum or minimum values. These points are known as local maximums or minimums, and they occur when the function changes direction from increasing to decreasing or vice versa. However, a function can only have one absolute maximum and one absolute minimum value within a given interval.

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