- #1
laker_gurl3
- 94
- 0
so the question is:
Complete the square of x^2 + 4x - 1 and hence find the position and value of its minimum.
AFter completing the square i have : (x+2)^2 - 5 ,
How do I find the minimum value from that?
Thanks in advance guys!
Complete the square of x^2 + 4x - 1 and hence find the position and value of its minimum.
AFter completing the square i have : (x+2)^2 - 5 ,
How do I find the minimum value from that?
Thanks in advance guys!