- #1
darshanpatel
- 139
- 0
The problem gave that:
theta= arcsin(-5/8)
It wants us to find the other five trig function values.
In order to do that, I turned the original function to
sin(theta)= - 5/8
From there I was able to find csc(theta) to be -8/5.
Using the pythagorian theorem I found the other side of the triangle that can be formed to be sqrt(39)
But because sin was negative from the original function, how are you supposed to figure out the quadrant the function lies in, because sin is negative in the 3rd and 4th quadrant.
I understand how to find the other values, I just don't which quadrant it lies in because it would effect the positive and negative signs.
theta= arcsin(-5/8)
It wants us to find the other five trig function values.
In order to do that, I turned the original function to
sin(theta)= - 5/8
From there I was able to find csc(theta) to be -8/5.
Using the pythagorian theorem I found the other side of the triangle that can be formed to be sqrt(39)
But because sin was negative from the original function, how are you supposed to figure out the quadrant the function lies in, because sin is negative in the 3rd and 4th quadrant.
I understand how to find the other values, I just don't which quadrant it lies in because it would effect the positive and negative signs.