That should be R+r in that last equation, since you are adding +r to both sides of the equation before it.ugodzilla said:
R is simply 23 ohms, not 23+.555
When you said that "V=emf - Ir", that V is the voltage across the 23 ohm resistor.ugodzilla said:
You're welcome, glad it worked out.ugodzilla said:
The formula for calculating pd is pd = emf - (r + R). This means that you subtract the sum of the resistance and load resistance from the electromotive force to get the potential difference.
Yes, you can still calculate pd without knowing the load resistance. You just need to know the resistance and emf values. The formula for this scenario is pd = emf - r.
Changing the resistance will directly affect the pd. As the resistance increases, the pd will decrease and vice versa. This is because resistance is inversely proportional to current, and pd is directly proportional to current. Therefore, as resistance increases, the current decreases, and the pd decreases as well.
If the load resistance is equal to the resistance, then the pd will be 0. This is because the formula for calculating pd becomes pd = emf - (r + r), which simplifies to pd = emf - 2r. Since r is equal to R, the equation becomes pd = emf - 2R, which means that the pd will be 0.
Yes, pd can be negative. This occurs when the load resistance is greater than the resistance and emf. In this scenario, the pd will be negative, indicating that the current is flowing in the opposite direction.