- #1
Adm_Thrawn
- 6
- 0
Homework Statement
A 20.0 V battery is connected across capacitors of capacitances C1 = C6 = 2.9 μF and C3 = C5 = 2.00C2 = 2.00C4 = 4.7 μF.
http://imgur.com/ssxTC
What are
(c) V1 and (d) q1 of capacitor 1,
(e) V2 and (f) q2 of capacitor 2,
(g) V3 and (h) q3 of capacitor 3,
Homework Equations
Ceq = c+c+c+c in parallel, 1/Ceq = 1/c+1/c+1/c in series
C=q/V
The Attempt at a Solution
I solved A and B for this problem, namely, the equivalent capacitance, and the charge.
C4 = 2.35, C2 = 2.35, C3 = 4.7, C5 = 4.7, C1 = 2.9, C6 = 2.9
1/C5 + 1/C3 = 2.35 + C2 + C4 = 7.05
C1 + C6 = 5.8
1/7.05 + 1/5.8 = 3.18e-6, which is the correct value for the C equivalence
Thus, 3.18e-6 = q/V(20) = q = 63.6e-6F
After this, I formed a small loop with the battery, C4 and C6.
Their C = 2.35 + 2.9 = 5.25e-6 = q/V(20), such that q = 1.05e-4
V = q/C4 = 44.68, but I know this can't be right because the potential can't be greater than the original potential, 20
I'm not certain where to go from here, in terms of finding the potential across or charge across these 3 resistors.