Finding Spring Stiffness and Effective Mass for Suspended Beam

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To find the maximum dynamic tension and frequency of vibration for a suspended 400 kg safe, the relevant equations include Newton's second law and the formula for angular frequency. The frequency was calculated correctly using ω=k/m, but the resultant force equation mg-T=ma requires acceleration, which is not provided. For a uniform beam suspended by two springs, the unloaded period is 0.83s and the loaded period is 1.52s, indicating that the spring stiffness can be derived from these periods. The effective mass of the beam and the stiffness of each spring can be calculated using the relationship between period and spring constant, but initial calculations may need adjustment for accuracy. Understanding the impact of loading on the system's dynamics is crucial for accurate results.
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Homework Statement


A cable is used to suspend a 400 kg safe. It is being lowered at 6 m/s, when it stops suddenly. Find the maximum dynamic tension and the frequency of vibration. k=2(105 N/m


Homework Equations



Newton's 2nd law

The Attempt at a Solution



Well I easily found the frequency using ω=k/m and got the correct answer.

If I find the resultant force in the direction of mg, I get mg-T=ma. I am not given a, I am given, v.


Homework Statement


A uniform beam is suspended by 2 springs A & B. Unloaded, the period of vertical vibration is 0.83s. When 50kg is loaded onto its centre, the period is 1.52s. Find the spring stiffness of each spring and the effective mass of the beam


Homework Equations





The Attempt at a Solution



The springs would be in parallel so

keq=2k

ω=√keq/m ⇒(2π/0.83)^2 (50) = 2k, but this does not give me the correct answer. k=608 N/m. I get 1432.66 N/m
 
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1) Right, the velocity they give you will be an initial condition that you can use with the general equation for a mass on a spring. Max tension should be at max deceleration.

2) It gives you the period for the unloaded beam. Once the beam is loaded with more mass it will have a different period. :)
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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