- #1
Seydlitz
- 263
- 4
Homework Statement
A curve is defined by the parametric equations:
x = 2t^3
y = 2t^2
t =/ 0
1)Prove that the equation of the tangent at the point with parameter t is 2x - 3ty + 2t^3 = 0. Proven, and I've no problem with this part.
2.)The tangent at the point t = 2 meets the curve again at the point where t = u. Find the value of u.
The Attempt at a Solution
I substituted the value of t = 2 to the first equation in problem 1.
It gives me 2x - 6y + 16 = 0
y = (1/6)(2x + 16)
At this point I'm stuck because ordinarily I'll just set the tangent equation equal to the curve, expressed in terms of x and then solve for x. But now with parametric equation I do not know how to proceed next or how to see the problem.
What is the condition required for a tangent to be said intersecting a parametric curve?
Thank You