Finding Tension ACB: Problem 2.53 Solution

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In summary, the conversation discusses problem 2.53 which asks for the tension in cable ACB. The answer is determined to be 1213N. There is a question about finding tension ACB and the speaker initially believes they need to find tensions CB and CA and then find the resultant of them. However, this is incorrect as the calculated tension CB also equals 1213N. The speaker then asks why tension ACB equals tension CB. The conversation also mentions the possibility of the traction cable not being present and the stability of the system in that case. The effect of a non-frictionless pulley is also brought up.
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CivilSigma
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For problem 2.53, they are asking us for the tension in cable ACB and the answer is 1213N.

Now to my understanding to find tension ACB, I need to find tension CB and CA then find the resultant of them, However I know that is wrong because when I calculated tension CB I got the answer of 1213N.

Now my question is, why is tension ACB = tension CB ?

Thank you in advance.
http://[Imgur](http://i.imgur.com/pOgJai9)
pOgJai9.jpg

dZyjo54.jpg
 
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If the traction cable were not there, what would happen? Is the system stable? What difference would it make if the pulley were not frictionless?
 

FAQ: Finding Tension ACB: Problem 2.53 Solution

What is the problem being solved in "Finding Tension ACB: Problem 2.53 Solution"?

The problem being solved is finding the tension in a rope or cable (represented by the variable T) that is supporting a mass (represented by the variable m) at an angle (represented by the variable θ) to the horizontal.

How is the tension (T) calculated in this problem?

The tension is calculated using the formula T = mgsin(θ), where g is the acceleration due to gravity (9.8 m/s²).

What information is needed to solve this problem?

To solve this problem, you will need to know the mass of the object being supported (m), the angle at which the rope or cable is attached to the object (θ), and the value of the acceleration due to gravity (g).

Can this formula be used for any angle?

Yes, this formula can be used for any angle as long as the angle is measured from the horizontal and the acceleration due to gravity is constant.

What are the units for tension (T) in this problem?

The units for tension in this problem will depend on the units used for mass (m), acceleration due to gravity (g), and the angle (θ). Typically, the units for tension are newtons (N) or pounds (lbs).

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