- #1
dahano
- 10
- 0
dahano said:I've tried some wild attempts but they landed me no where :-
Qwertywerty said:Please post these attempts .
However I still give a hint :
What does dy/dx represent ?
What is the formula for Range ?
Sorry to ask a stupid question but what do you mean by point? Can you please show me how would it be solved?andrevdh said:The angle of projection can be found from the gradient of the graph at what point?
dahano said:I figured out the formula of range as: u2Sin2(theta)/g
Can you tell me that how would it be done further?
Please attach your working for this.dahano said:I figured out the formula of range as: u2Sin2(theta)/g
The angle of projection in 2D Kinetics refers to the angle at which an object is launched or thrown. It is measured with respect to the horizontal plane.
The angle of projection can be calculated using trigonometric functions, such as sine, cosine, and tangent. It can also be determined by using vector analysis.
The angle of projection is affected by factors such as the initial velocity of the object, the height at which it is launched, and the angle at which it is released.
The speed of projection in 2D Kinetics is the initial velocity at which an object is launched or thrown. It is a vector quantity and is measured in meters per second (m/s).
The speed of projection can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. It can also be determined using vector analysis.