Finding the Aperture Size for 1-Arcsec Resolution at 500nm Wavelength

[Benzoate]

Homework Statement

What apeture is required to give 1-arcsec resolution for a wavelength of 500 nm(visible)

Homework Equations

theta=wavelength/d ; d is the size of the apeture

The Attempt at a Solution

I'm assuming when they are asking for the apeture , they are asking for the size of the apeture.

theta=wavelength/d => d=wavelength/theta =

I converted 1 arc second to 5*10^-6 radian

d=500*10^-9 m/5*10^-6= .1 m

 

[learningphysics]

Looks right to me.

 

[m2003]

Therefore, the aperture size required for 1-arcsec resolution at 500nm wavelength would be 0.1 meters. This means that the aperture must have a diameter of 0.1 meters (or 10 centimeters) in order to achieve 1-arcsec resolution at a wavelength of 500nm. It is important to note that this calculation assumes perfect conditions and does not take into account any potential limitations or factors that may affect the resolution. Further experimentation and analysis may be necessary to determine the optimal aperture size for achieving 1-arcsec resolution at 500nm wavelength.