Finding the Center and Radius of a Circle: Analytic Geometry I

In summary, the circle x²+y²-4x+2y+6=0 cannot be defined because r² = -1 is impossible. To find the centre and radius of a circle, the equation can be expressed as x²+y²+2fx+2gy+c=0, where C(-f,-g) is the centre and the radius is √(g²+f²-c). It is better to complete the square rather than memorize formulas to avoid mistakes.
  • #1
kLownn
7
0

Homework Statement


Find the centre and radius of the circle x²+y²-4x+2y+6=0

I have the solution. The circle is no defined because r² = -1 is impossible.
But... how do I even DO that equation to get the answer -1?!
 
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  • #2
You complete the squares so you can write it in the form (x+a)^2+(y+b)^2=c. Do you know how to do that?
 
  • #3
Dick said:
You complete the squares so you can write it in the form (x+a)^2+(y+b)^2=c. Do you know how to do that?

I learned how to do that while I was in school.. I forget how to do it now.. >_<
 
  • #4
Take the x part. You've got x^2-4x. If I add something to that it will become a perfect square of the form (x-a)^2. What's 'a'? What do you have to add?
 
  • #5
Dick said:
Take the x part. You've got x^2-4x. If I add something to that it will become a perfect square of the form (x-a)^2. What's 'a'? What do you have to add?

Oh! Is "a" 2x?
(x-2x)² ?
 
  • #6
No, no. (x-a)^2=x^2-2ax+a^2, yes? If you match that up with x^2-4x, the 4 must be the 2a, as I see it. Think back to when you did this before.
 
  • #7
Dick said:
No, no. (x-a)^2=x^2-2ax+a^2, yes? If you match that up with x^2-4x, the 4 must be the 2a, as I see it. Think back to when you did this before.

Ohh, I see now.. so I just do the same thing for y?
 
  • #8
kLownn said:
Ohh, I see now.. so I just do the same thing for y?

Sure.
 
  • #9
Dick said:
Sure.

Thank you so much! :)
 
  • #10
kLownn said:

Homework Statement


Find the centre and radius of the circle x²+y²-4x+2y+6=0

I have the solution. The circle is no defined because r² = -1 is impossible.
But... how do I even DO that equation to get the answer -1?!

it can actually be express as x²+y²+2fx+2gy+c=0

whrby C(-f,-g) and radius is [tex]\sqrt{g²+f²-c}[/tex]
 
  • #11
icystrike said:
it can actually be express as x²+y²+2fx+2gy+c=0

whrby C(-f,-g) and radius is [tex]\sqrt{g²+f²-c}[/tex]
No, it isn't. It is much better to actually do the "complete the square" rather than memorize formulas: so you don't make silly mistakes like that.
 
  • #12
HallsofIvy said:
No, it isn't. It is much better to actually do the "complete the square" rather than memorize formulas: so you don't make silly mistakes like that.

yep (: noted.
 

FAQ: Finding the Center and Radius of a Circle: Analytic Geometry I

1. What is the equation of a circle in standard form?

The equation of a circle in standard form is (x - h)^2 + (y - k)^2 = r^2, where (h,k) is the center of the circle and r is the radius.

2. How do you find the center and radius of a circle given its equation?

To find the center and radius of a circle given its equation, you can rewrite the equation in standard form and compare it to the general equation. The values of h and k will give the coordinates of the center, and the square root of r^2 will give the radius.

3. Can a circle have a negative radius?

No, a circle cannot have a negative radius. A negative radius would imply that the circle is drawn in the opposite direction, which is not possible.

4. How do you find the length of an arc on a circle?

To find the length of an arc on a circle, you can use the formula L = rθ, where r is the radius and θ is the central angle in radians. If the angle is given in degrees, you can convert it to radians by multiplying by π/180.

5. What is the difference between a circle and a sphere?

A circle is a two-dimensional shape, while a sphere is a three-dimensional shape. A circle is formed by all the points on a plane that are equidistant from a central point, whereas a sphere is formed by all the points in space that are equidistant from a central point.

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