- #36
The Electrician
Gold Member
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- 210
Your first short paragraph above describes the situation as shown in the schematic of post #1.BvU said:My turn to be confused: if ##V_2=+64## V, the CCVS delivers ##-##64 V and pumps 3.8 A towards point V2. The ##-##64 is 20 times the ##-##3.2 A ##i_\Delta##.
If the CCVS sets ##V_2=+ 6.80851 ## V, the dial must read ##-6.80851 ## V which is minus 20 times the then ##-##0.34 A ##i_\Delta##.
The second short paragraph describes what would happen if the CCVS control law were changed from 20 IΔ to -20 IΔ, or if the orientation of the CCVS were flipped upside down with no change to the control law.
That's what Baluncore is referring to when he says "reverse the CCVS polarity".