Finding the Correct Acceleration in a Spinning Circle: What Am I Doing Wrong?

In summary, the student attempted to solve for w using the cross products and got the correct answer, but is having difficulty with y. They are using radian measure and may be having issues with the equation.
  • #1
BryMan92
18
0

Homework Statement



See image.

Homework Equations


ωx (ωx r) = anormal
αx r =atangent

x=rcos*theta
y=-rsin*theta

The Attempt at a Solution



I solved for w=2 k rad/s and α= -1.5 k rad/s

I also got the correct answer using the cross products. My problem is I am trying to do this problem in rectangular coordinates (I really like rectangular), but I am doing something wrong and I cannot see it.

So, I assume r is constant:
x''=-r*cos(45)[ω^2-α] = Correct answer= -15.566

BUT, y'' is giving me a headache:
I keep getting rsin(45)[ω^2-α] and I get = 15.66 and NOT the right answer of 7.07 in/s. There is a lurking negative sign and I cannot find it. That - should be a + and then I get a correct answer. Am I just deriving incorrectly?

Thanks!
And apologizes if this is pretty novice: its from my Junior-level engineering class...or a freshman Physics class. ;p
 

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  • #2
from the problem you know that va = 8 in/sec and aa=6 in/sec/sec

and you know that va is tangent to the circle and that aa is along the radius

so the unit vector for aa=cos (theta) i + sin(theta) j

and the unit vector for va = - sin(theta) i + cos(theta) j

now figure out theta and factor in the vector magnitudes into the unit vector equations to get the vector equations of motion.

Lastly, if you do unit vector va dot aa = -sin(theta) cos(theta) + cos(theta) sin(theta) = 0 meaning they are perpendicular as a check
 
  • #3
That make's sense. Shouldn't I be able to use y=-rsin*theta to kind of derive that? Everything you said makes perfect sense (I do like the dotting notion!), but I am still wondering why rectangular equation has issues.
 
  • #4
you should be able to start with s(x,y) and then diferentiate to get va
and differentiate again to aa.

s(x,y) = R*cos(w*t + offset)) i + R*sin(w*t + offset) j

make sure you're using radian measure for all angle values that could be where your problem lies.
 
  • #5
I would first like to commend you for your efforts in trying to solve this problem and for seeking help when you encounter difficulties. It demonstrates your determination and willingness to learn, which are key qualities in a scientist.

Now, let's get to the problem at hand. It seems like you have a good understanding of the equations and concepts involved in solving this problem. However, there are a few things that you may have overlooked.

Firstly, when solving problems in rectangular coordinates, it is important to remember that the x and y components of acceleration are independent of each other. This means that the equations for x and y acceleration should be solved separately.

Secondly, in the equation for y acceleration, you have used the wrong angle. The angle in the y direction is not 45 degrees, but rather 90 degrees. This is because the y direction is perpendicular to the x direction in a circle. So the correct equation for y acceleration would be y'' = -r*sin(90)[ω^2-α], which gives the correct answer of 7.07 in/s.

Lastly, it is always a good practice to double check your calculations and equations to make sure you have not made any mistakes. Sometimes, a simple error in calculation or a misplaced negative sign can lead to incorrect answers.

In conclusion, it seems like you have a good understanding of the concepts involved in solving this problem. Just make sure to pay attention to the details and double check your work to avoid any mistakes. Keep up the good work and don't be afraid to seek help when needed. Good luck!
 

FAQ: Finding the Correct Acceleration in a Spinning Circle: What Am I Doing Wrong?

What is a point on a spinning circle?

A point on a spinning circle refers to a specific location on the circumference of a circle that is rotating or spinning around a fixed point, also known as the center.

2. How does the position of a point on a spinning circle change?

The position of a point on a spinning circle changes as the circle rotates. The point will move along the circumference of the circle in a circular motion, while also maintaining a fixed distance from the center.

3. What factors affect the speed of a point on a spinning circle?

The speed of a point on a spinning circle is affected by the radius of the circle, the angular velocity (rate of rotation) of the circle, and the distance of the point from the center of the circle. A larger radius, higher angular velocity, and greater distance from the center will result in a faster speed for the point.

4. What is the relationship between the speed and position of a point on a spinning circle?

The speed and position of a point on a spinning circle are directly related. As the position of the point changes, so does its speed. When the point is at the top of the circle, it is moving at its fastest speed. As the point moves towards the bottom of the circle, its speed decreases and reaches zero when it is back at the bottom.

5. How is a point on a spinning circle related to centripetal force?

A point on a spinning circle is related to centripetal force as it experiences an inward force towards the center of the circle in order to maintain its circular motion. This force is provided by the tension in the string or the force of friction acting on the point.

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