If the center is the point (3,5), this means the y-coordinate represents the distance from the line y = 0 to y = 5.MarkFL said:Begin by plotting the point (3,5)...now given the circle is tangent to the $x$-axis, what must the radius be?
The equation of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h,k) is the center of the circle and r is the radius.
The center of the circle is represented by (h,k) in the equation. To find the center, solve for h and k. The radius of the circle is the square root of r^2 in the equation.
Yes, the center and radius can be negative. This just means that the circle is centered at a point that is not on the origin and has a radius smaller than the distance from the origin to the center point.
The equation of a circle represents all the points that are a certain distance (radius) from a given point (center). The graph of the equation is a circle with the center at the given point and the radius as its distance from the center.
Yes, the equation of a circle can also be written as (x - a)^2 + (y - b)^2 = c, where (a,b) is the center of the circle and c is the square of the radius. This form is called the standard form of the equation of a circle.