Finding the Greatest Common Divisor in Java: A Beginner's Guide

  • Java
  • Thread starter JaysFan31
  • Start date
  • Tags
    Gcd Method
In summary, the conversation primarily revolved around finding the greatest common divisor of two integers in Java without using the Euclidean Algorithm. The participant shared their code and asked for feedback and suggestions for improvement. Another participant pointed out some mistakes and offered a simpler and more efficient way of finding the GCD using a loop or a recursive function. They also explained the difference between using "&&" and "||" in the code and shared their own version of the code using a loop. The conversation concluded with a recursive function using Euclid's algorithm as the most efficient solution.
  • #1
JaysFan31
I am a beginner programmer in Java. Just started learning the past few weeks.

I'm taking a class and need to create a method that finds the greatest common divisor of two integers. I can assume that both are positive, but I cannot use the Euclidean Algorithm.

I'm sort of lost, but I think I'm on the right track, although this may look confusing:
Code:
public static int gcd(int a, int c)
{
int gcd;
int attempt;
if (a > c)
{
 if (a % c == 0)
{
gcd = c;
return gcd;
}
else
{
for (attempt = c; attempt = 1; attempt--)
do
{
if (c % attempt == 0 && a % attempt == 0)
{
gcd = attempt;
return attempt;
}
}
while (c % attempt != 0 || a % attempt == 0);
}
}
And then I basically copied the code with an else statement if c > a.

I'm sure there are a lot of mistakes. Could someone just point them out and offer a simpler way of doing it (possibly without using the Euclidean Algorithm)?

Thanks.
Michael
 
Technology news on Phys.org
  • #2
If you have a for loop, I don't think you want to use a variable with a larger scope as the counter variable. And you also don't need to copy the code for the case c > a. You can say "if a % c == 0 || c % a = 0 {return min(a,c);}" and make the for loop only run up to min(a,c). This isn't too creative though, as you can guess. But other than your straightforward approach above and the Euclidean Algorithm, I can't think of any other ways to find the gcd.
 
Last edited:
  • #3
The way you used a local variable "int gcd" inside the function with the same name "public static int gcd(...)" is confusing (though not actually wrong).

In Java you can just say

return c;

instead of

gcd = c;
return gcd;

I wonder if you found some Fortran code and tried to translate it into Java. In Fortran you would write something like

function gcd(...)
integer gcd
...
gcd = c
return

But that (slightly strange) syntax is specific to Fortran, Java and C are different.

The efficient way to find the GCD is Euclid's algorithm (look it up on Google). You can either write the code using a loop, or use a recursive function. (If you haven't gone recursion yet, come back to this later.)
 
Last edited:
  • #4
OK. I think this is a lot better. It compiles and makes sense to me at least. However, it doesn't work properly for more difficult integers like 20, 30. Can anyone spot the problem (as I said nothing wrong with compiling, just doesn't work logically). As I said before, I can't use the Euclidean Algorithm, so I basically had to write the simplest program to find gcd.

Code:
public static int gcd(int a, int b)
{
int gcd;
if (a > b && a % b == 0)
{
gcd = b;
return gcd;
}
else if (b > a && b % a == 0)
{
gcd = a;
return gcd;
}
else if (a > b && a % b != 0)
{
int count = b;
do
{
count = count - 1;
}
while (b % count != 0 && a % count != 0);
gcd = count;
return gcd;
}
else if (b > a && b % a != 0)
{
int count = a;
do
{
count = count - 1;
}
while (b % count != 0 && a % count != 0);
gcd = count;
return gcd;
}
else
{
gcd = a;
return gcd;
}
}
 
  • #5
You have got confused between "&&" to "||" which is a common mistake. Often in English you say "and" when you really mean "or", and vice versa.

Actually, the "do {...} while(...)" statement with a complicated "while(...)" condition is often hard to understand, and it is quite a rare statement in most Java programs.

A loop which tests at the top, "while(...) { ... }" is much more common. If you use that form of loop, then "&&" is the correct operator and the statement means the same read "in English" and "in Java".

There is another advantage of testing at the start of the loop - it gives you the possibility of doing nothing, if the condition is true before you get to the loop. That is often useful.

It's certainly useful calculating the gcd, because it handles all your special cases like a = b, a > b and a & b = 0, etc.

I came up with this version, which handles all the cases the same way:

public static int gcd(int a, int b)
{
int count = a;
if (b < a)
{
count = b;
}

while (a % count != 0 && b % count != 0)
{
count = count - 1;
}
return count;
}

A recursive function using Euclid's algorithm is even shorter:

public static int gcd(int a, int b)
{
if (a % b == 0)
return b;
else
return gcd(b, a % b);
}
 
Last edited:

FAQ: Finding the Greatest Common Divisor in Java: A Beginner's Guide

What is the purpose of finding the greatest common divisor in Java?

The greatest common divisor (GCD) in Java is used to find the largest number that divides two or more given numbers without leaving any remainder. It is commonly used in mathematical calculations and can also be used to simplify fractions.

What is the most efficient way of finding the GCD in Java?

The most efficient way of finding the GCD in Java is by using the Euclidean algorithm. This algorithm uses successive division to find the GCD of two numbers and is significantly faster than other methods, especially for large numbers.

Can the GCD be negative?

No, the GCD cannot be negative. It is always a positive number because it represents the largest common factor between two or more numbers, which cannot be negative.

Is there a built-in function for finding the GCD in Java?

Yes, there is a built-in function in the Java Math library called gcd() that can be used to find the GCD of two numbers. This function uses the Euclidean algorithm and returns an integer value representing the GCD.

Can the GCD be used for more than two numbers?

Yes, the GCD can be used for any number of numbers. The Euclidean algorithm can be applied recursively to find the GCD of multiple numbers by finding the GCD of the first two numbers, then finding the GCD of that result and the next number, and so on.

Similar threads

Replies
13
Views
4K
Replies
1
Views
1K
Replies
6
Views
4K
Replies
2
Views
2K
Replies
1
Views
2K
Replies
1
Views
1K
Replies
3
Views
3K
Replies
5
Views
2K
Back
Top