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Homework Statement
Find the inverse Laplace transform of the following function
1/[s(s2 + 4)2]
Homework Equations
1/ (s2 + [itex]\omega[/itex]2)2 = (1/ 2[itex]\omega[/itex]3) (sin[itex]\omega[/itex]t -[itex]\omega[/itex]t cos[itex]\omega[/itex]t)
The Attempt at a Solution
L-1 = (1/s) (1/ s2 +22)2
= (1/16) (sin 2t - 2t cos 2t) as the Laplace transform of (1/s) = 1
Is this what I am meant to do?