- #1
r_swayze
- 66
- 0
Im having trouble with this problem here:
x-->0 tan6x / sin2x
So far I only have:
(sin6x / cos6x) / (2sinx cosx)
What would be the next step? Multiply the reciprocal?
Also, could somebody tell me if I am doing this problem right?
x--> 0 (sin (cosx)) / secx
sin (cosx) / 1/cosx
sin (cosx) cosx
sin (1) 1 = sin 1
x-->0 tan6x / sin2x
So far I only have:
(sin6x / cos6x) / (2sinx cosx)
What would be the next step? Multiply the reciprocal?
Also, could somebody tell me if I am doing this problem right?
x--> 0 (sin (cosx)) / secx
sin (cosx) / 1/cosx
sin (cosx) cosx
sin (1) 1 = sin 1
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