Finding the Next Collision Point in an Elastic Collision Problem

In summary, the problem involves an elastic collision between two masses with known velocities and a spring that is within the 53cm distance between the masses. The objective is to determine the distance from the end of the track where the second collision between the masses will occur, using the equations of motion and the known velocity of the center of mass. The solution also requires knowledge of the spring constant and rest length, which are not given in the problem.
  • #1
OVB
32
0

Homework Statement


A mass of .59 kg and a velocity of - 0.75 m/s approaches a stationary mass of 0.35 kg that is 53 cm away from the edge of a wall. The stationary (m2) pushes against a spring (elastic collision) that is within the 53cm of separation and reverses direction. How far from the end of the track does the next collision occur?


Homework Equations



vcm = (m1v1)/M = -0.47m/s




The Attempt at a Solution



I think i need to find the time between the first and second collisions, and then use this to find the second xcm (using the vcm I already know), relative to the first collision, and this should get me the answer, but I am not sure how to find the time it takes for the second collision.
 
Physics news on Phys.org
  • #2
Here is some useful background on elastic collisions.

http://hyperphysics.phy-astr.gsu.edu/hbase/colsta.html

http://hyperphysics.phy-astr.gsu.edu/hbase/elacol2.html

An elastic collision is defined as one in which both conservation of momentum and conservation of kinetic energy are observed. This implies that there is no dissipative force acting during the collision and that all of the kinetic energy of the objects before the collision is still in the form of kinetic energy afterward.

One needs to determine the velocities of each mass after the collision, then determined the equations of motion for each, and then solve for the position where the two particles meet (at the same time).

When a larger mass collides with a (smaller) mass, the large mass will continue in the same direction, assuming the collision is 'head on'. The smaller mass will rebound in the direction of the velocity large mass. In the case of the spring, the spring starts to compress which slows the second mass, until either the larger mass catches up to the smaller mass, or the smaller mass changes direction and collides with the larger mass.

To obtain a numerical solution, one needs the spring constant and rest length of the spring. Or, is the rest length of the spring 53 cm?
 
  • #3
Oh, I understood the background info, it's the spring that's confusing me. The diagram shows it is small compared to the 53cm so I can't say what its length is. Since I don't know the k (or how to solve for it since there is no length of spring or force given) I can't determine the time between the initial collision between the smaller mass and the spring and the final release point of the mass on its way back.
 

FAQ: Finding the Next Collision Point in an Elastic Collision Problem

What is an elastic collision?

An elastic collision is a type of collision where the total kinetic energy of the system is conserved. This means that the total energy before the collision is equal to the total energy after the collision.

How is the velocity of objects before and after an elastic collision related?

In an elastic collision, the velocity of the objects before and after the collision are related by the equation: v1before + v2before = v1after + v2after, where v1 and v2 are the velocities of the two objects involved in the collision.

Can an elastic collision occur between two objects with different masses?

Yes, an elastic collision can occur between two objects with different masses. The conservation of energy and momentum principles still apply, and the velocity of the lighter object will be greater than the velocity of the heavier object after the collision.

How does the coefficient of restitution affect an elastic collision?

The coefficient of restitution is a measure of the elasticity of a collision. In an elastic collision, the coefficient of restitution will be equal to 1, indicating a perfectly elastic collision. A lower coefficient of restitution indicates a less elastic collision, meaning some kinetic energy is lost during the collision.

Is an elastic collision possible in real life?

While it is difficult to achieve a perfectly elastic collision in real life, many everyday collisions can be approximated as elastic. Examples include collisions of billiard balls, bouncing balls, and collisions between gas particles. In these cases, the energy lost due to friction and other factors is relatively small compared to the total energy of the system.

Similar threads

Replies
16
Views
3K
Replies
5
Views
2K
Replies
4
Views
1K
Replies
22
Views
3K
Replies
4
Views
4K
Replies
2
Views
2K
Replies
4
Views
1K
Back
Top