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Homework Statement
Determine the peak value of current of:
[tex]\underline{I} = \frac{120\angle0^0}{10+j10}[/tex]
The Attempt at a Solution
I change this into polar form and got:
[tex]\underline{I} = 12.0 \angle -45^0[/tex]
Therefore, the peak value of the current should be 12.0 A. However, the solution key says 8.4853 A. How can this be so?
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