- #1
SwAnK
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Hey I was given the question:
A (x1,y1) and B (x2,y2) are two points on the parabola y=ax^2+bx+c. At what point is the tangent to the parabola parallel to the secant AB.
Here are the steps I took, I am just wanting to know if I am heading in the right direction.
First I just made the slope of AB = m.
then found the derivative of ax^2+bx+c (2ax+1) and made m=2ax+1.
Then isolated x, which would give an x coordinate of m/2a+1.
Took the x value and subed it into the equation ax^2+bx+c to get a y value.
Is this how you would go about this question?? thanx
A (x1,y1) and B (x2,y2) are two points on the parabola y=ax^2+bx+c. At what point is the tangent to the parabola parallel to the secant AB.
Here are the steps I took, I am just wanting to know if I am heading in the right direction.
First I just made the slope of AB = m.
then found the derivative of ax^2+bx+c (2ax+1) and made m=2ax+1.
Then isolated x, which would give an x coordinate of m/2a+1.
Took the x value and subed it into the equation ax^2+bx+c to get a y value.
Is this how you would go about this question?? thanx