- #1
leprofece
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Find the curve coordinates nearest to P
a)x2 = y P(3,0)
ok to the boox exercise model I must do so
(x-3)2+ (y)2 = D
then x2-6x +9+y2 = D
introducing y into x
y-6sqrt(y) +9 + (y)2 = D
derivating
1-3/(sqrt(y) +0+2y
mcm = sqrt(y) -3 +2y = 0
solving
sqrt(y) = -2y+3
Squaring
y = 4y2-12y +9
4y2-13y +9 = 0
x = 1
y = 1
a)x2 = y P(3,0)
ok to the boox exercise model I must do so
(x-3)2+ (y)2 = D
then x2-6x +9+y2 = D
introducing y into x
y-6sqrt(y) +9 + (y)2 = D
derivating
1-3/(sqrt(y) +0+2y
mcm = sqrt(y) -3 +2y = 0
solving
sqrt(y) = -2y+3
Squaring
y = 4y2-12y +9
4y2-13y +9 = 0
x = 1
y = 1