Finding the pressure in a pipe?

In summary, the conversation discussed finding the pressure at a point along the 810 mile long Alaskan pipeline, where the radius changes from 60cm to 30cm. The pipeline has a capacity of 2.48e5 m^3/day of oil and the given pressure at the section with a 60cm radius is 190kPa. It was assumed that the flow is laminar and nonviscous, with a density of 800 kg/m^3. The proposed equation to find the pressure is Pi + [rho(q^2)]/2pi^2 * (1/Ri^4 * R^4), and the validity of the equation was questioned based on its units.
  • #1
miamirulz29
62
0

Homework Statement


The 810 mile long alaskan pipeline has a capacity of 2.48e5 m^3/day of oil per day. Along most the pipeline the radius is 60cm. Find the pressure at a point where the pipe has a 30cm radius. Take the pressure in the section with radius 60cm to be 190kPa and the density of oil to be 800 kg/m^3. Assume laminar nonviscous flow. Answer in units kPa


Homework Equations


q= delta v/ delta t


The Attempt at a Solution


My final equation is Pi + [rho(q^2)]/2pi^2 * (1/Ri^4 * R^4).
Is that correct?
 
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  • #2
A quick way that you can check your equation is with the units.

Does you equation produce a unit in kPa?

Thanks
Matt
 
  • #3


I would first clarify the units of the given data. The capacity of the pipeline is given in cubic meters per day, while the radius is given in centimeters. Therefore, the first step would be to convert the radius to meters (1 meter = 100 centimeters). This would give us a radius of 0.6 meters for the section with radius 60cm and 0.3 meters for the section with radius 30cm.

Next, I would use the equation for pressure in a pipe, which is P = rho*g*h, where P is pressure, rho is density, g is the acceleration due to gravity, and h is the height of the column of fluid. In this case, we can assume h to be the length of the pipeline (810 miles = 1.3e6 meters). So, the pressure at the section with radius 60cm would be P = 800 kg/m^3 * 9.8 m/s^2 * 1.3e6 m = 10.24e9 N/m^2 = 10.24 GPa.

To find the pressure at the section with radius 30cm, we can use the equation P = rho*g*h * (Ri^2/R^2), where Ri is the initial radius (60cm) and R is the final radius (30cm). This would give us a pressure of P = 800 kg/m^3 * 9.8 m/s^2 * 1.3e6 m * (0.6^2/0.3^2) = 20.48e9 N/m^2 = 20.48 GPa.

Finally, we can convert the pressure to kPa by dividing by 1000, giving us a pressure of 10.24 GPa = 10.24e6 kPa for the section with radius 60cm and 20.48 GPa = 20.48e6 kPa for the section with radius 30cm. Therefore, the pressure at the point where the pipe changes from 60cm to 30cm radius is 20.48e6 kPa.
 

FAQ: Finding the pressure in a pipe?

What is the formula for finding pressure in a pipe?

The formula for finding pressure in a pipe is pressure = force/area. This means that the pressure in a pipe is equal to the force applied divided by the cross-sectional area of the pipe.

How do you measure the pressure in a pipe?

The pressure in a pipe can be measured using a pressure gauge. This is a device that measures the force per unit area exerted by a fluid in the pipe, typically in units of psi (pounds per square inch) or kPa (kilopascals).

What factors affect the pressure in a pipe?

The pressure in a pipe is affected by several factors, including the volume and velocity of the fluid flowing through the pipe, the diameter and length of the pipe, and the elevation and temperature of the pipe. Changes in these factors can result in changes in the pressure within the pipe.

How does pressure change in a pipe with depth?

The pressure in a pipe increases with depth due to the weight of the fluid above pushing down on the lower layers of the fluid. This increase in pressure with depth is known as hydrostatic pressure.

What is the maximum pressure that a pipe can handle?

The maximum pressure that a pipe can handle depends on the material and thickness of the pipe, as well as the type of fluid flowing through it. It is important to follow manufacturer guidelines and safety regulations to ensure that the pressure in a pipe does not exceed its maximum capacity.

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