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free2rhyme12345
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Consider 3 force vectors F1, F2, and F3. The vector F1 has magnitude F1 = 55N and direction θ = 41°; the vector F2 has magnitude F2 = 20N and direction θ = - 140°; and the vector F3 has magnitude F3 = 17N and direction θ = 140°. All the direction angles θ are measured from the positive x axis: counter-clockwise for θ > 0 and clockwise forr θ < 0.
A. What is the magnitude F or the net force vector F = F1+F2+F3? Answer in units of N.
B. What is the direction of the net force vector F? State your answer as an angle θ between -180° and +180°. Answer in units of °.
Horizontal: F*sin(θ) = x
Vertical F*cos(θ) = y
I found the x resultants to be 10.93 + 12.85 + 36.08 = 59.86
y resultants: 13.0227 + 41.50 + 15.32 = 69.8427
Then I added them and got 129.70745, but that is wrong.
Please help me solve this question, I have no idea how to do it.
A. What is the magnitude F or the net force vector F = F1+F2+F3? Answer in units of N.
B. What is the direction of the net force vector F? State your answer as an angle θ between -180° and +180°. Answer in units of °.
Horizontal: F*sin(θ) = x
Vertical F*cos(θ) = y
I found the x resultants to be 10.93 + 12.85 + 36.08 = 59.86
y resultants: 13.0227 + 41.50 + 15.32 = 69.8427
Then I added them and got 129.70745, but that is wrong.
Please help me solve this question, I have no idea how to do it.
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