- #1
Shukie
- 95
- 0
I have the following equation:
[tex]2a \sinh(\frac{25}{a}) = 51[/tex]
How do I solve this for a?
I tried changing it to:
[tex]a(e^{\frac{25}{a}} - e^{\frac{-25}{a}}) = 51[/tex], but that didn't get me any further. Anyone?
[tex]2a \sinh(\frac{25}{a}) = 51[/tex]
How do I solve this for a?
I tried changing it to:
[tex]a(e^{\frac{25}{a}} - e^{\frac{-25}{a}}) = 51[/tex], but that didn't get me any further. Anyone?