Finding the solution to system of 3 equations with 3 unknowns

In summary, the conversation discusses how the equations ##2x_1 - 8x_3 = 4## and ##-2x_1+8x_3= -4## cannot hold at the same time, leading to the conclusion that the solution space is empty and there is nothing more that can be done. The unexpected result of ##0 \ne 1## is accepted and no values for ##x_1## or ##x_3## will satisfy the equation.
  • #1
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Homework Statement
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Relevant Equations
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For this,
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I am trying to find solutions, however, I think I am getting a strange result that I am not too sure how to intercept.

I first multiply the first equation by 2 to get ##2x_1 - 8x_3 = 4## and then I add it to the second equation below to get ##0 = 1##. I think this means that there is no values for ##x_1## or ##x_3## that satisfy the equation. I am not too sure how to go from here but I know ##x_2## is a leading variable of the third equation.

Any help is greatly appreciated

Many thanks!
 
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  • #2
ChiralSuperfields said:
I first multiply the first equation by 2 to get ##2x_1 - 8x_3 = 4## and then I add it to the second equation below to get ##0 = 1##. I think this means that there is no values for ##x_1## or ##x_3## that satisfy the equation.
Right. If you multiply the first line by ##-2## then you get ##-2x_1+8x_3= -4## and ##-2x_1+8x_3= -3.##
This cannot hold at the same time.
ChiralSuperfields said:
I am not too sure how to go from here but I know ##x_2## is a leading variable of the third equation.

Any help is greatly appreciated

Many thanks!
The solution space is empty. There is nothing left that can be done.
 
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  • #3
ChiralSuperfields said:
get ##0 = 1##. I think this means that there is no values for ##x_1## or ##x_3## that satisfy the equation. I am not too sure how to go from here
Good work. Sometimes the hardest problems are the ones that give you an unexpected result. Just double-check your result and accept what it says. Your result is not just about ##x_1## and ##x_3##, it is about ##0 \ne 1##. So nothing more can be done.
 
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FAQ: Finding the solution to system of 3 equations with 3 unknowns

What methods can be used to solve a system of 3 equations with 3 unknowns?

There are several methods to solve a system of 3 equations with 3 unknowns, including substitution, elimination (also known as the addition method), and matrix methods such as Gaussian elimination and using the inverse of a matrix.

How do you solve a system of 3 equations with 3 unknowns using substitution?

To solve using substitution, solve one of the equations for one variable in terms of the others, then substitute this expression into the other two equations. Repeat the process to reduce the system to two equations with two unknowns, and then to one equation with one unknown. Solve for the unknowns step-by-step and back-substitute to find the remaining variables.

What is Gaussian elimination and how is it used to solve a system of 3 equations with 3 unknowns?

Gaussian elimination involves transforming the system of equations into an upper triangular matrix using row operations. Once in this form, back-substitution is used to solve for the unknowns starting from the last equation and moving upwards. This method is systematic and can be easily implemented using matrices.

Can a system of 3 equations with 3 unknowns have no solution or infinitely many solutions?

Yes, a system of 3 equations with 3 unknowns can have no solution if the equations represent parallel planes that do not intersect, or it can have infinitely many solutions if the equations represent the same plane or intersect along a line. Consistency and dependency of the equations determine the nature of the solutions.

How can you verify the solution to a system of 3 equations with 3 unknowns?

To verify the solution, substitute the values of the unknowns back into the original equations. If the left-hand side of each equation equals the right-hand side for all three equations, then the solution is correct. This ensures that the values satisfy all the given equations simultaneously.

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