Finding the Sum of a Convergent Power Series

In summary, you can integrate n^2.x^n to get the sum, but you need to start with a series you know and derive an expression for it.
  • #1
mathmathmad
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Homework Statement



evaluate ∑ n^2.x^n where 0<x<1

Homework Equations





The Attempt at a Solution


let a_n = n^2 and c=0
then radius of convergence, R=1
hence the series convergences when |x|<1
let f(x) = ∑ n^2.x^n
then f'(x) = ∑ n^3.x^n-1 for n=0 to infinity
then f'(x) = ∑ (n+1)^3.x^n for n=1 to infinity

from here, how to I derive a function ∑ (n+1)^3.x^n so as to integrate it to get the sum?
 
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  • #2
Hi mathmathmad! :smile:

(have an infinity: ∞ and try using the X2 and X2 tags just above the Reply box :wink:)
mathmathmad said:
let f(x) = ∑ n^2.x^n
then f'(x) = ∑ n^3.x^n-1 for n=0 to infinity
then f'(x) = ∑ (n+1)^3.x^n for n=1 to infinity …

Why are you making it more complicated? :redface:

Hint: try integrating. :wink:
 
  • #3
differentiating is a much better option fyi
 
  • #4
It's somewhat hard to start from your f(x) and find a series you know.

Instead, try starting from a series you know and apply these methods to get f(x).
 
  • #5
what to integrate?
intergrate n^2.x^n?
 
  • #6
mathmathmad said:
what to integrate?
intergrate n^2.x^n?

Sort-of.

Suppose it was ∑ nxn … what would you integrate? :wink:
 
  • #7
I still say (expanding a little on my hint) to start with an expression for

∑ xn

and try to derive an expression for your series.
 
  • #8
Hi Mathnerdmo! :smile:
Mathnerdmo said:
It's somewhat hard to start from your f(x) and find a series you know.

Instead, try starting from a series you know and apply these methods to get f(x).
Mathnerdmo said:
I still say (expanding a little on my hint) to start with an expression for

∑ xn

and try to derive an expression for your series.

ah, i see what you mean now …

your method is basically the same as mine, but in reverse …

i'm integrating the question to try to get something easier, while you're starting with something easier, and differentiating to get the question. :wink:

Yes, if mathmathmad wants to start with ∑ xn and differentiate it, that's fine. :smile:
 

FAQ: Finding the Sum of a Convergent Power Series

What is a power series?

A power series is an infinite series of the form f(x) = a0 + a1x + a2x2 + a3x3 + ..., where a0, a1, a2, a3, ... are constant coefficients and x is the variable. It is a representation of a function as an infinite sum of terms with increasing powers of x.

What is the purpose of evaluating a power series?

The purpose of evaluating a power series is to determine the behavior of a function at a particular value of x. By finding the sum of the series, we can approximate the value of the function at that point and also analyze its convergence and divergence properties.

What is the process of evaluating a power series?

The process of evaluating a power series involves finding the sum of the series by adding up the terms up to a desired number of terms. This is usually done using a mathematical formula or by using a computer program. The more terms that are included, the more accurate the evaluation will be.

Can all functions be represented by a power series?

No, not all functions can be represented by a power series. The function must have a finite value at each point in its domain and its behavior must be smooth and continuous. Some functions, such as piecewise-defined or discontinuous functions, cannot be represented by a power series.

How can we determine the convergence of a power series?

The convergence of a power series can be determined by using various tests, such as the ratio test, root test, or integral test. These tests help to determine if the series approaches a finite limit, diverges to infinity, or oscillates. It is important to check the convergence of a power series before evaluating it to ensure accuracy.

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