Finding the time using the acceleration (forces)

In summary, the conversation discusses the problem of finding the acceleration and time it takes for a raft with a total mass of 195kg, being affected by ocean currents and wind forces, to travel 4km. The solution involves using the equation Distance = (0.5)(acceleration)(time^2) to find the time, with the acceleration being calculated as 0.62m/s/s at a direction of 50.9 degrees. The conversation also mentions that the question was originally posted in the advanced physics section, but should have been posted in the introductory physics section.
  • #1
ilovemynny
24
0

Homework Statement



Joey is now on a raft in the ocean, try to sail home. The raft + Joey have a total mass of 195kg. The ocean current produceds a force of 60N eastwaard and the wind produces a force of 95N at 80 degrees. Find the acceleration of the raft (magnitude and direction). If these forces are constant, how long will it take Little Joey to travel 4km?

Homework Equations



So I figured out the magnitude of acceleration which is 0.62m/s/s and the direction of acceleration is 50.9 degrees.


The Attempt at a Solution



To find Time
would I use this equation: Distance = (0.5)(a)(t^2)
?
if so, would it be

4000m = (0.5)(0.62m/s/s)(t^2)

and just solve t from there?
 
Physics news on Phys.org
  • #2
That seems reasonable, doesn't it?

This probably doesn't belong in the advanced physics section, by the way.
 
  • #3
awesome :D thank you!

sorry >.< the reason why i put it in advanced is because I'm taking ap physics right now >.< i didn't know where to put it
 
  • #4
That's OK. The advanced physics section is for "upper-division (college junior or senior) and graduate-level questions.", so for next time the introductory physics section would be better - you'll get a quicker reply that way, more people read it!
 
  • #5


I would first confirm that the given forces are indeed constant. If they are, then I would use Newton's Second Law (F=ma) to calculate the acceleration of the raft, taking into account both the eastward and 80 degree forces. With the magnitude and direction of acceleration, I would then use the kinematic equation d=vt + 0.5at^2 to calculate the time it would take for the raft to travel 4km. It is important to note that this equation assumes constant acceleration, which may not be the case in real-life scenarios. To account for any changes in acceleration, I would need to use a more complex equation, such as d=vt + 0.5at^2 + 0.5j(t^2), where j represents the change in acceleration over time. Overall, it is important to carefully consider the assumptions and limitations of any equations used in solving this problem.
 

FAQ: Finding the time using the acceleration (forces)

How do you calculate time using acceleration?

To calculate time using acceleration, you can use the formula t = v/a, where t is time, v is velocity, and a is acceleration. This formula works for objects with a constant acceleration.

Can you find the time without knowing the acceleration?

No, it is not possible to find the time without knowing the acceleration. Acceleration is a necessary component in the equation for calculating time.

What is the difference between instantaneous and average acceleration?

Instantaneous acceleration refers to the acceleration of an object at a specific moment in time, while average acceleration is the overall change in velocity over a specific period of time.

How does acceleration affect the time it takes for an object to reach a certain velocity?

Acceleration directly affects the time it takes for an object to reach a certain velocity. The greater the acceleration, the shorter the time it takes for an object to reach a specific velocity.

Can acceleration be negative?

Yes, acceleration can be negative. This means that the object is slowing down or decelerating. Positive acceleration indicates that the object is speeding up.

Similar threads

Replies
6
Views
4K
Replies
1
Views
1K
Replies
1
Views
2K
Replies
20
Views
2K
Replies
6
Views
2K
Replies
5
Views
1K
Replies
6
Views
1K
Back
Top