MHB Finding the Value of $\log_{10}\left({5*\sqrt[3]{14}}\right)$

  • Thread starter Thread starter cbarker1
  • Start date Start date
  • Tags Tags
    Value
AI Thread Summary
To find the value of $\log_{10}\left({5*\sqrt[3]{14}}\right)$, the user starts by breaking it down into components: $\log_{10}\left({5}\right)$ and $\log_{10}\left({\sqrt[3]{14}}\right)$. The latter is expressed as $\frac{1}{3}[\log_{10}\left({2}\right)+\log_{10}\left({7}\right)]$. The user seeks to determine $\log_{10}\left({5}\right)$, using the relationship $\log_{10}\left({5}\right)=1-\log_{10}\left({2}\right)$. The discussion emphasizes the importance of clearly stating problems for effective assistance.
cbarker1
Gold Member
MHB
Messages
345
Reaction score
23
I need some help finding the value of this $\log_{10}\left({5*\sqrt[3]{14}}\right)$

With
$$\log_{10}\left({2}\right)=.30$$ $$\log_{10}\left({3}\right)=.48$$ and $\log_{10}\left({7}\right)=.85$ is given in the textbook.

First I use
$\log_{10}\left({5}\right)+\log_{10}\left({\sqrt[3]{14}}\right)$
I use
$\log_{10}\left({5}\right)+\frac{1}{3}*[\log_{10}\left({2}\right)+\log_{10}\left({7}\right)]$
I need to how to find out the $\log_{10}\left({5}\right)$ and I know how to use the values above into the expression.

Thank
Cbarker
 
Mathematics news on Phys.org
Cbarker1 said:
I need some help finding the value of this $\log_{10}\left({5*\sqrt[3]{14}}\right)$

With
$$\log_{10}\left({2}\right)=.30$$ $$\log_{10}\left({3}\right)=.48$$ and $\log_{10}\left({7}\right)=.85$ is given in the textbook.

First I use
$\log_{10}\left({5}\right)+\log_{10}\left({\sqrt[3]{14}}\right)$
I use
$\log_{10}\left({5}\right)+\frac{1}{3}*[\log_{10}\left({2}\right)+\log_{10}\left({7}\right)]$
I need to how to find out the $\log_{10}\left({5}\right)$ and I know how to use the values above into the expression.

Thank
Cbarker

$\log_{10}\left({5}\right)=\log_{10}\left({\frac{10}{2}}\right)=\log_{10}\left({10}\right)-\log_{10}\left({2}\right)=1-\log_{10}\left({2}\right)$
 
Cbarker1 said:
I need some help finding the value of this $\log_{10}\left({5*\sqrt[3]{14}}\right)$

With
$$\log_{10}\left({2}\right)=.30$$ $$\log_{10}\left({3}\right)=.48$$ and $\log_{10}\left({7}\right)=.85$ is given in the textbook.

First I use
$\log_{10}\left({5}\right)+\log_{10}\left({\sqrt[3]{14}}\right)$
I use
$\log_{10}\left({5}\right)+\frac{1}{3}*[\log_{10}\left({2}\right)+\log_{10}\left({7}\right)]$
I need to how to find out the $\log_{10}\left({5}\right)$ and I know how to use the values above into the expression.

Thank
Cbarker

I just wanted to make the comment that your post could be used as a model for effectively getting help. You clearly stated the problem and what you did and where you are stuck. Well done! (Yes)
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads

Replies
1
Views
1K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
1
Views
4K
Replies
2
Views
2K
Replies
5
Views
1K
Replies
15
Views
4K
Back
Top