- #1
wubie
Hello,
I am still unsure of my ability to evaluate the volume of a solid using triple integrals. Here is my question:
Now I know that the intersection of the two paraboloids is
9 = x^2 + y^2.
But I am unsure how to set up the triple integral. I was thinking of splitting the volume into two halves.
But as I am writing this I am not sure that I have to do that. I would say I could set up the triple integral with the following limits of integration as so:
Let E be the solid in question. Then
E = {(x,y,z) | -3 <= x <= 3, -(9-x^2)^1/2 <= y <= (9-x^2)^1/2, x^2 + y^2 <= z <= 36 - 3x^2 - 3y^2 }
How does this look? First I would integrate with respect to z, then y then x.
I was thinking that I could split the solid into two triple integrals as such:
E = {(x,y,z) | -3 <= x <= 3, -(9-x^2)^1/2 <= y <= (9-x^2)^1/2, x^2 + y^2 <= z <= 9 }
and
E = {(x,y,z) | -3 <= x <= 3, -(9-x^2)^1/2 <= y <= (9-x^2)^1/2, 9 <= z <= 36 - 3x^2 - 3y^2 }
But I don't see a problem with the first way I set up the triple integral. However I haven't tried to integrate it as of yet.
Any thoughts on the problem would be appreciated. Thankyou.
I am still unsure of my ability to evaluate the volume of a solid using triple integrals. Here is my question:
Find the volume of the region bounded by the paraboloids
z = x^2 + y^2
and
z = 36 - 3x^2 - 3y^2
Now I know that the intersection of the two paraboloids is
9 = x^2 + y^2.
But I am unsure how to set up the triple integral. I was thinking of splitting the volume into two halves.
But as I am writing this I am not sure that I have to do that. I would say I could set up the triple integral with the following limits of integration as so:
Let E be the solid in question. Then
E = {(x,y,z) | -3 <= x <= 3, -(9-x^2)^1/2 <= y <= (9-x^2)^1/2, x^2 + y^2 <= z <= 36 - 3x^2 - 3y^2 }
How does this look? First I would integrate with respect to z, then y then x.
I was thinking that I could split the solid into two triple integrals as such:
E = {(x,y,z) | -3 <= x <= 3, -(9-x^2)^1/2 <= y <= (9-x^2)^1/2, x^2 + y^2 <= z <= 9 }
and
E = {(x,y,z) | -3 <= x <= 3, -(9-x^2)^1/2 <= y <= (9-x^2)^1/2, 9 <= z <= 36 - 3x^2 - 3y^2 }
But I don't see a problem with the first way I set up the triple integral. However I haven't tried to integrate it as of yet.
Any thoughts on the problem would be appreciated. Thankyou.