Finding the X Component of the Center of Mass of a Cut-Out Square Plate

So the X component would be 6.25/28.56 * -1.7 = -0.371 m. In summary, the center of mass for the remaining plate is located at (-0.371, 0) when measured from the origin at the center of the plate.
  • #1
BlasterV
38
0
A uniform square plate L = 5.9 m on a side as a square section d = 2.5 m cut out of one side.

What is the center of mass of the remaining plate? Use a coordinate system with origin (0, 0) at the center of the plate.

The answer must be given in components.

X = ?
Y = ?. From the picture it is obvious the Y component is 0, so Y = 0 is correct. (and the auto-grade says correct also, so Y = 0 ).

However, exactly how to find the X component I can't figure out.

I tried 2-3 different ways of doing it, and none have worked, does anyone know exactly how to solve this problem for the X component? I tried a few things like splitting it up and using weighted averages but it is not working or I have the wrong equation.

Thanks! I am attaching a picture of the problem.
 

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  • #2
BlasterV said:
I tried a few things like splitting it up and using weighted averages but it is not working or I have the wrong equation.

Thanks! I am attaching a picture of the problem.

This should work. Can you show your calculations ?

marlon
 
  • #3
(Assume it is constant 1kg)

(5.9m(1kg) ) / (1kg) = 5.9m <- from the Y axis, for center 5.9/2 = 2.95m
This goes for top and bottom sections.

(5.9m-2.5m)(1kg) / (1kg) <- 3.4m <- from the Y ais, for center 5.9/2 = 1.7m

1.7m(1kg) + 2.95m(1kg) + 2.95(1kg) / (3kg) = 2.53m

Since the origin (0,0) is in center of Square, center of x = 2.95m, 2.53 - 2.95 = -.417 m from the origin.

I don't think this is right, this is my work tho
 
  • #4
BlasterV said:
A uniform square plate L = 5.9 m on a side as a square section d = 2.5 m cut out of one side.

What is the center of mass of the remaining plate? Use a coordinate system with origin (0, 0) at the center of the plate.

The answer must be given in components.

X = ?
Y = ?. From the picture it is obvious the Y component is 0, so Y = 0 is correct. (and the auto-grade says correct also, so Y = 0 ).

However, exactly how to find the X component I can't figure out.

I tried 2-3 different ways of doing it, and none have worked, does anyone know exactly how to solve this problem for the X component? I tried a few things like splitting it up and using weighted averages but it is not working or I have the wrong equation.

Thanks! I am attaching a picture of the problem.

First of all, the question is not complete. Are we given that the plate is cut out of the center of one side, so that the figure has a line of symmetry parallel to a side of the large square ?

Failing that condition, we have to take a general case, letting the distance between the top edge of the cut piece and one edge of the main plate be y, and then working out the center of mass in terms of y.

Divide the figure into 3 rectangles and find the center of mass of each in the coordinate system specified. See attached figure.

Then figure out the mass of each rectangle. In this case, you can use area as a proxy for mass, since the thickness and density are uniform.

Finally use the formula [tex]\Sigma m_i(x_i,y_i) = M(X,Y)[/tex] to derive an expression for the overall center of mass.

This is a rather tedious problem if you have to assume the general case.
 

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  • #5
Decompose the remaining plate into 3 rectangles and use the axis symmetry to find the result...

Daniel.
 
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  • #6
I am absolutely sure about Y = 0. Besides that, only things known are D and L
 
  • #7
A far more elegant solution than decomposing into 3 rectangles is to take the big plate before cutting as one mass with center of mass at the origin. The second mass is a negative mass of the cut portion with the center of mass given in terms of the variable (depending on position). The final mass M is the difference between the two. This cuts down on a lot of calculation and yields the correct answer much more smartly.
 
  • #8
Using my last method, here is the short and elegant solution.

Let the cut portion be taken out of the right edge such that the distance between the top edge of the cut portion and the top edge of the main plate is y.

M is the mass of the whole plate before cutting, m is the mass of the cut portion. Coordinates represented in square brackets to avoid confusion. [X, Y] is the position of the center of mass of the final figure.

Then :

[tex]M[0,0] - m[1.7,1.7 - y] = (M-m)[X,Y][/tex]

[tex](-(2.5)^2)[1.7, 1.7 - y] = (5.9^2 - 2.5^2)[X,Y][/tex]

[tex][X,Y] = \frac{6.25}{28.56}[-1.7, (y - 1.7)][/tex]
 

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  • #9
So the answer to the X component would be -1.7? or 6.25/28.56 * -1.7?
 
  • #10
BlasterV said:
So the answer to the X component would be -1.7? or 6.25/28.56 * -1.7?

The latter. The factor should be multiplied by each coordinate.
 

FAQ: Finding the X Component of the Center of Mass of a Cut-Out Square Plate

What is the Center of Mass Problem?

The Center of Mass Problem is a physics problem that involves identifying the point at which an object's mass is evenly distributed in all directions, known as the center of mass. This point is important in understanding an object's motion and stability.

How is the Center of Mass Calculated?

The Center of Mass is calculated by finding the weighted average of an object's individual mass and position values. This can be done using the formula: x̄ = (m1x1 + m2x2 + ... + mnxn) / (m1 + m2 + ... + mn), where x̄ is the position of the center of mass and m is the mass at each position.

What is the significance of the Center of Mass in Physics?

The Center of Mass is significant in physics because it allows us to simplify complex systems into a single point. This is useful in understanding an object's overall motion and predicting how it will behave under various forces.

Can the Center of Mass be outside of an object?

Yes, the Center of Mass can be outside of an object. This can happen when an object has an irregular shape or when the mass is distributed unevenly. However, the Center of Mass will always be located within the boundaries of the object.

How does the Center of Mass affect an object's stability?

The Center of Mass plays a crucial role in an object's stability. If the Center of Mass is located above the base of support, the object will be stable. However, if the Center of Mass is located outside of the base of support, the object will be unstable and may topple over.

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