Finding Triples to Satisfy $\frac{5}{2}$

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In summary, finding triples to satisfy $\frac{5}{2}$ means finding three numbers that, when multiplied together, equal $\frac{5}{2}$. It can be important in various mathematical and scientific applications, and can be found using techniques such as trial and error or algebraic manipulation. There can be multiple sets of triples that satisfy $\frac{5}{2}$, and these triples can be negative or fractions.
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anemone
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Find all triples $(a,\,b,\,c)$ of positive integers such that $\dfrac{a}{b}+\dfrac{c}{a}+\dfrac{b}{c+1}=\dfrac{5}{2}$.
 
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  • #2
anemone said:
Find all triples $(a,\,b,\,c)$ of positive integers such that $\dfrac{a}{b}+\dfrac{c}{a}+\dfrac{b}{z+1}=\dfrac{5}{2}$.

what s z ?
 
  • #3
It's a typo...$z$ is supposed to be a $c$.

I will fix my original post right now, and thanks for catching that...:D
 

FAQ: Finding Triples to Satisfy $\frac{5}{2}$

What does it mean to find triples to satisfy $\frac{5}{2}$?

Finding triples to satisfy $\frac{5}{2}$ means finding three numbers that can be multiplied together to equal $\frac{5}{2}$. This is also known as finding a solution to the equation $xyz = \frac{5}{2}$.

Why is it important to find triples to satisfy $\frac{5}{2}$?

Finding triples to satisfy $\frac{5}{2}$ can be important in various mathematical and scientific applications. For example, in geometry, finding triples to satisfy $\frac{5}{2}$ can help in constructing right triangles with a specific ratio of side lengths. In physics, it can be used to solve for unknown variables in equations that involve $\frac{5}{2}$.

How do you find triples to satisfy $\frac{5}{2}$?

There are multiple ways to find triples to satisfy $\frac{5}{2}$. One approach is to use trial and error, plugging in different values for each variable until a solution is found. Another approach is to use algebraic manipulation, such as factoring or substitution, to solve for the variables.

Are there multiple sets of triples that can satisfy $\frac{5}{2}$?

Yes, there can be multiple sets of triples that can satisfy $\frac{5}{2}$. For example, if we let $x = 1$, then $y = 5$ and $z = \frac{1}{2}$ would satisfy the equation $xyz = \frac{5}{2}$. However, if we let $x = \frac{1}{2}$, then $y = 10$ and $z = \frac{1}{2}$ would also satisfy the equation. These are two different sets of triples that satisfy $\frac{5}{2}$.

Can triples be negative or fractions when solving for $\frac{5}{2}$?

Yes, triples can be negative or fractions when solving for $\frac{5}{2}$. For example, if we let $x = -2$, then $y = -\frac{5}{2}$ and $z = \frac{1}{2}$ would satisfy the equation $xyz = \frac{5}{2}$. This is a valid solution, as the product of these three numbers is still equal to $\frac{5}{2}$.

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