Finding Velocity given angle and distance.

In summary, the conversation discusses finding the velocity of an object thrown at 45 degrees above the horizontal that travels 60 m before hitting the ground. The summary provides the necessary equations and steps to solve for the initial velocity, which is calculated to be 24.24 m/s.
  • #1
odyssey4001
5
0

Homework Statement


The questions is, that if you throw something at exactly 45 degrees above the horizontal and it travels 60 m before hitting the ground what's it velocity?


Homework Equations


Physic's equation, see below


The Attempt at a Solution



Horizontal Component
Vh = cos 45
= 0.707

now t = 60/0.707
=84.86

Vertical Component
Vv = 0.707 - gt

What do I do now? Am I right to this point as well?
 
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  • #2
Welcome to PF.

The first thing to do is start over.

Thrown at 45 degrees means that vertical and horizontal speeds are the same.

So how long is it in the air? Vy/g is the time to go up ... so total time (up and down) is 2*Vy/g

And how fast is it going to go 60 m?

a = 60 = Vx*t = Vx*2*Vy/g

Since Vx = Vy then just solve.
 
  • #3
LowlyPion said:
Welcome to PF.

The first thing to do is start over.

Thrown at 45 degrees means that vertical and horizontal speeds are the same.

So how long is it in the air? Vy/g is the time to go up ... so total time (up and down) is 2*Vy/g

And how fast is it going to go 60 m?

a = 60 = Vx*t = Vx*2*Vy/g

Since Vx = Vy then just solve.


Ok cool, so is Vy cos 45 = 0.707? so then Vy = Vx = 0.707?
 
  • #4
odyssey4001 said:
Ok cool, so is Vy cos 45 = 0.707? so then Vy = Vx = 0.707?

No.

.707 is merely the value of cos45 and sin45.

Your mission is to figure out what the initial velocity is.
 
  • #5
LowlyPion said:
No.

.707 is merely the value of cos45 and sin45.

Your mission is to figure out what the initial velocity is.

ok so is this right,

Vo = [tex]\sqrt{(g*d)/(2 sin Theta*cos Theta)}[/tex]

Vo = [tex]\sqrt{(9.8*60) / (2 sin 45*cos 45)}[/tex]

Vo = 24.24
 
  • #6
That would be correct.
 

FAQ: Finding Velocity given angle and distance.

How do I calculate velocity given an angle and distance?

To calculate velocity with an angle and distance, you can use the formula v = d/t, where v is velocity, d is distance, and t is time. However, if you have an angle, you will also need to use trigonometry to find the horizontal and vertical components of the velocity. You can use the equations vx = vcosθ and vy = vsinθ, where vx is the horizontal velocity, vy is the vertical velocity, and θ is the angle.

What units should I use when finding velocity with an angle and distance?

When using the formula v = d/t to find velocity, the units for velocity will be the same as the units for distance divided by the units for time. For example, if the distance is measured in meters and the time is measured in seconds, then the velocity will be in meters per second (m/s). When using trigonometry to find horizontal and vertical components of velocity, the units for velocity will be the same as the units for the original velocity, as the trigonometric functions do not change the units.

Can velocity be negative when finding it with an angle and distance?

Yes, velocity can be negative when using the formula v = d/t to find velocity. Negative velocity indicates that the object is moving in the opposite direction of the positive direction defined in the problem. When using trigonometry to find horizontal and vertical components of velocity, the components can also be negative depending on the angle and direction of motion.

What if I have the velocity and angle, but not the distance?

If you have the velocity and angle, but not the distance, you can still use the formula v = d/t to find the distance. Rearrange the formula to d = vt, where d is distance, v is velocity, and t is time. However, if you have an angle, you will also need to use trigonometry to find the horizontal and vertical components of the velocity, and then use the Pythagorean theorem to find the total distance.

Can I use this method to find velocity in all situations?

This method can be used to find velocity in situations where the object is moving at a constant speed in a straight line. If the object is accelerating or moving in a curved path, more advanced equations and methods would need to be used. Additionally, this method assumes that the angle and distance are both accurate measurements, so in some cases, it may not be the most precise method.

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