Finding Velocity on a Position/Time Graph

In summary, the conversation is about finding velocity on a straight line position/time graph. The person is using the equation Vf-Vi/Tf-ti to calculate velocity, but is getting different answers. They are also confused about the slope of the line and are looking for clarification.
  • #1
5pirit
1
0
Hey everyone, I'm having trouble finding velocity on a straight line position/time graph. Every single equation I do ends up with a different answer, which doesn't make sense because it's a straight line.

I know the equation is

Vf-Vi/Tf-ti

The answer to this question is 1.4m/s N

Example:

45-25/28-16= 1.666666m/s Wrong answer. I'm just taking these from the graph by the way.

25-20/16-14= 2.5, completely different answer.

Could someone please explain what I'm doing wrong? I'm calculating the slope which seems to change with every calculation that I do, which I understand is wrong.
 
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  • #2
Try to post the graph so we can see it. Also, if your v is velocity, you are dividing a velocity change by an elapsed time. That gives acceleration. If you want velocity, divide displacement by time.
 
  • #3
5pirit said:
Hey everyone, I'm having trouble finding velocity on a straight line position/time graph. Every single equation I do ends up with a different answer, which doesn't make sense because it's a straight line.

I know the equation is

Vf-Vi/Tf-ti

The answer to this question is 1.4m/s N

Example:

45-25/28-16= 1.666666m/s Wrong answer. I'm just taking these from the graph by the way.

25-20/16-14= 2.5, completely different answer.

Could someone please explain what I'm doing wrong? I'm calculating the slope which seems to change with every calculation that I do, which I understand is wrong.
Hello 5pirit. Welcome to PF !

What is the slope of that line?
 

Related to Finding Velocity on a Position/Time Graph

1. How do you find the velocity on a position/time graph?

The velocity on a position/time graph can be found by calculating the slope of the line at a specific point. This can be done by finding the change in position (y-axis) over the change in time (x-axis) at that point.

2. What is the difference between average velocity and instantaneous velocity?

Average velocity is the overall rate of change of position over a specific period of time, while instantaneous velocity is the velocity at a specific moment in time. Average velocity is represented by the slope of a line connecting two points on a position/time graph, while instantaneous velocity is represented by the slope of the tangent line at a specific point on the graph.

3. How do you calculate the slope of a line on a position/time graph?

The slope of a line on a position/time graph can be calculated by dividing the change in position (y-axis) by the change in time (x-axis) between two points on the line. This can be represented by the formula: slope = (y2 - y1) / (x2 - x1).

4. What does a horizontal line on a position/time graph represent?

A horizontal line on a position/time graph represents an object at rest, with a velocity of 0. This means that there is no change in position over time, and the object is not moving.

5. Can the velocity of an object be negative on a position/time graph?

Yes, the velocity of an object can be negative on a position/time graph. This would indicate that the object is moving in the opposite direction of the positive direction on the graph. For example, a negative velocity on a position/time graph could represent an object moving backwards.

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