- #1
chupe
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Consider the region bounded by the curves y=x^2+1 and y=3-x^2
a) using the disk/washer method, find the volume of the solid obtained by rotating this region about the x axis
This was very straight forward
v=int(1, -1) pi((3-x^2)^2)-(x^2+1)^2))dx
I finished the problem with 32pi/3 which I think is correct.
However the next part I have no idea how to set up using the disk washer method.
b) Set up the integral for finding the volume of the solid obtained by rotating about the y-axis.
I know that the integration will have to be done in parts but I don't know where to split it into parts. If someone could help me set up the question that would be amazing.
Thank you,
Cheers
a) using the disk/washer method, find the volume of the solid obtained by rotating this region about the x axis
This was very straight forward
v=int(1, -1) pi((3-x^2)^2)-(x^2+1)^2))dx
I finished the problem with 32pi/3 which I think is correct.
However the next part I have no idea how to set up using the disk washer method.
b) Set up the integral for finding the volume of the solid obtained by rotating about the y-axis.
I know that the integration will have to be done in parts but I don't know where to split it into parts. If someone could help me set up the question that would be amazing.
Thank you,
Cheers