Finding V's Rate of Change for h = 0.60cm

In summary, the purpose of finding V's rate of change for h = 0.60cm is to determine the instantaneous rate of change of V with respect to h at h = 0.60cm. This is calculated by taking the derivative of the function V with respect to h and plugging in the value of h = 0.60cm. A positive rate of change indicates a direct relationship between V and h, while a negative rate of change indicates an inverse relationship. The units of V's rate of change for h = 0.60cm will depend on the units of V and h. This concept can be applied in various real-life situations, such as determining speed, chemical reactions, and growth rates. It is
  • #1
ve3rfd
8
0
Hi, I had a question that wanted me to find the instantaneous rate of change of V with respect to h for h = 0.60cm. The equation was V = 1/6*pi*h^3 + 2.00*pi*h and I retrieved an answer of 6.85 cm/s. Could anyone tell me if that is correct? Thanks.
 
Physics news on Phys.org
  • #2
The derivative of V with respect to h and then plug in .6 cm...

looks correct to me
 
  • #3
To two decimal places, yes. In future it would be better to show your work rather than just the answer.
 

FAQ: Finding V's Rate of Change for h = 0.60cm

What is the purpose of finding V's rate of change for h = 0.60cm?

The purpose of finding V's rate of change for h = 0.60cm is to determine the instantaneous rate of change of the variable V with respect to the variable h at h = 0.60cm. This can provide valuable information about the relationship between V and h and can help in making accurate predictions or calculations.

How is V's rate of change for h = 0.60cm calculated?

V's rate of change for h = 0.60cm is calculated by taking the derivative of the function V with respect to h and then plugging in the value of h = 0.60cm. This will give the slope of the tangent line to the graph of V at h = 0.60cm, which represents the instantaneous rate of change of V at that point.

What does a positive/negative rate of change for h = 0.60cm indicate?

A positive rate of change for h = 0.60cm indicates that as h increases, V also increases. This means that V and h are directly proportional and as one variable increases, the other also increases. On the other hand, a negative rate of change for h = 0.60cm indicates an inverse relationship between V and h, where as h increases, V decreases.

What are the units of V's rate of change for h = 0.60cm?

The units of V's rate of change for h = 0.60cm will depend on the units of V and h. If V is measured in cm^3 and h is measured in cm, then the units of V's rate of change for h = 0.60cm will be cm^3/cm. It is important to pay attention to the units when interpreting the rate of change.

How can finding V's rate of change for h = 0.60cm be applied in real-life situations?

Finding V's rate of change for h = 0.60cm can be applied in various real-life situations, such as determining the speed of an object at a specific time, calculating the rate of change of a chemical reaction, or predicting the growth rate of a population. It can also be useful in engineering and physics for designing and analyzing systems and structures.

Similar threads

Back
Top