- #1
binbagsss
- 1,307
- 11
I am guessing that:
$R_{a[bcd]}=0$
can not be derived from the symmetries of
$R_{ab(cd)]}=R_{(ab)cd}=0$
$R_{[ab][cd]}=0$ ?Sorry when I search the proof for it I can not find much, it tends to come up with the covariant Bianchi instead.
I am guessing it will need one of the symmetries above (at least) and the second covariant Bianchi identity to prove it?
Thanks
$R_{a[bcd]}=0$
can not be derived from the symmetries of
$R_{ab(cd)]}=R_{(ab)cd}=0$
$R_{[ab][cd]}=0$ ?Sorry when I search the proof for it I can not find much, it tends to come up with the covariant Bianchi instead.
I am guessing it will need one of the symmetries above (at least) and the second covariant Bianchi identity to prove it?
Thanks