- #1
MrGandalf
- 30
- 0
I was stumped by this differential equation. The function x = x(t).
[tex]x^{\tiny\prime\prime} + \frac{1}{t}x^{\tiny\prime} = 0[/tex].
You have the initial values x(a) = 0 and x(1) = 1.
What I did was to introduce a new function u = x', so I ended up with the first order homogenous DE:
[tex]u^{\tiny\prime} + \frac{1}{t}u = 0[/tex].
This can't be that difficult, but the book which I am using does not give any details how to solve this particular problem. I only know how to solve it if I have a constant, or a function of t, on the right side.
The solution to the problem is:
[tex]x(t) = 1 - \frac{\log t}{\log a}[/tex].
Hope someone can shed some light on this. Thank ye, ye scurvy landlubber! Yarrr!
[tex]x^{\tiny\prime\prime} + \frac{1}{t}x^{\tiny\prime} = 0[/tex].
You have the initial values x(a) = 0 and x(1) = 1.
What I did was to introduce a new function u = x', so I ended up with the first order homogenous DE:
[tex]u^{\tiny\prime} + \frac{1}{t}u = 0[/tex].
This can't be that difficult, but the book which I am using does not give any details how to solve this particular problem. I only know how to solve it if I have a constant, or a function of t, on the right side.
The solution to the problem is:
[tex]x(t) = 1 - \frac{\log t}{\log a}[/tex].
Hope someone can shed some light on this. Thank ye, ye scurvy landlubber! Yarrr!
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