- #1
Rajini
- 621
- 4
Hello All,
I am trying to fit a curve by exponential growth. See the attached photo for curve. I want to fit that curve with expo growth function.
We know that growth decay function is ##N_{t}=N_{0}\times e^{\lambda t}##. Exponential part is positive as this is a growth function.
Is the function ##N_{t}=b+[N_{0}\times e^{\lambda (t-t_0)}]## is correct growth function for my curve shown in the photo? I am confused with ##(t-t_0)## part.
##b##=baseline, ##N_0##=peak height or see photo, ##\lambda##=1/meanlife time, ##t_0##=see photo, from ##t_0## decays to the left side.
PS: I think the function ##N_{t}=b+[N_{0}\times e^{\lambda (t-t_0)}]## accounts for the curve just before/left side of ##t_0##. But I need to use the full curve to fit. So kindly inform me how can I use the straight line at ##t_0## in the growth function.
Thanks for reply.
Cheers, Rajini.
I am trying to fit a curve by exponential growth. See the attached photo for curve. I want to fit that curve with expo growth function.
We know that growth decay function is ##N_{t}=N_{0}\times e^{\lambda t}##. Exponential part is positive as this is a growth function.
Is the function ##N_{t}=b+[N_{0}\times e^{\lambda (t-t_0)}]## is correct growth function for my curve shown in the photo? I am confused with ##(t-t_0)## part.
##b##=baseline, ##N_0##=peak height or see photo, ##\lambda##=1/meanlife time, ##t_0##=see photo, from ##t_0## decays to the left side.
PS: I think the function ##N_{t}=b+[N_{0}\times e^{\lambda (t-t_0)}]## accounts for the curve just before/left side of ##t_0##. But I need to use the full curve to fit. So kindly inform me how can I use the straight line at ##t_0## in the growth function.
Thanks for reply.
Cheers, Rajini.
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