- #1
Apteronotus
- 202
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In a book on synchronization it is stated that given the ODE
[tex]\frac{d\psi}{dt}=-\nu+\epsilon q(\psi)[/tex]
there is at least one pair of fixed points if
[tex]\epsilon q_{min}<\nu<\epsilon q_{max}[/tex]
were [tex]q_{min}, q_{max}[/tex] are the min and max values of [tex]q(\psi)[/tex] respectively.
While this could be true under particular circumstances (ie. when [tex]q_{min}<0, q_{max}>0[/tex]), I don't see how it could hold in general; such as the case when [tex]q(\psi)>0[/tex].
Can anyone shed some light on this?
Thanks in advance.
[tex]\frac{d\psi}{dt}=-\nu+\epsilon q(\psi)[/tex]
there is at least one pair of fixed points if
[tex]\epsilon q_{min}<\nu<\epsilon q_{max}[/tex]
were [tex]q_{min}, q_{max}[/tex] are the min and max values of [tex]q(\psi)[/tex] respectively.
While this could be true under particular circumstances (ie. when [tex]q_{min}<0, q_{max}>0[/tex]), I don't see how it could hold in general; such as the case when [tex]q(\psi)>0[/tex].
Can anyone shed some light on this?
Thanks in advance.