Flex Your Mathletic Muscles Impress the Ladies

  • Thread starter eNtRopY
  • Start date
In summary, a few days ago in the physics board, a differential equation of the form y' = k * y^(1/2) was encountered. The asker, eNtRopY, asked for help in solving the equation and mentioned that it had been a long time since they had taken a class on the techniques of solving differential equations. They were hoping someone could impress the "beautiful ladies" on the board by solving it for them. Another user pointed out that the equation was separable and provided the solution y = (k*x/2 + C)^2. eNtRopY thanked them and admitted they should have seen it themselves.
  • #1
eNtRopY
A few days ago in the physics board, we encountered the following differential equation of the form:

y' = k * y^(1/2).

It's been a long time since I've taken a class in the techniques of solving differential equation, and I can't remember off-hand how to solve this problem. Rather than research the method for solving this problem myself, I thought I'd give you dudes a chance to impress all the beautiful ladies on these boards (e.g. Entropia, Kerrie, Galatea, Kat, Monique, Saint, etc.).

eNtRopY

P.S. If you are a lady, and I have forgotten you, I'm sorry... I don't have a very good memory for names.
 
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  • #2
In other words, you're lazy and you want us to do your work for you. :smile:

This equation is seperable:

dy/dx = k * y^(1/2)

y^(-1/2) * dy = k * dx
 
  • #3
Lazy... or too busy?
Anyway,

y = (k*x/2 + C)^2

Thanks... I don't know why I didn't see that right away. I guess I should be embarrassed.

eNtRopY
 
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  • #4
Originally posted by eNtRopY
Lazy... or too busy?
Anyway,

y = (k*x/2)^2

Thanks... I don't know why I didn't see that right away. I guess I should be embarrassed.

eNtRopY

You forgot to add a constant before squaring.
 

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