- #1
Ragnar1995
- 10
- 0
Homework Statement
In a horizontal rectangular open channel 20 m wide the water depth is 9 m. When a
smooth hump 1.5 m high is introduced in the channel floor, a drop of 1 m is produced in
the water surface. What is the flow rate, neglecting energy losses? It is proposed to place
a pier at the centre of this channel on the hump. Determine the maximum width of this
pier if it is not to cause any backwater effects.
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Homework Equations
all the equations i can think of are :
E=h+(v^2/2g) also h+(v^2/2g)=constant
E=h+(q^2/2gh^2)
hc=(q^2/g)^1/3
Emin=1.5hc
Q=qB
E1=y+E2
v=q/h
Where E=specific energy
h=depth of flow
hc=critical depth
q=flow rate per unit width
Q=flow rate[/B]
The Attempt at a Solution
First of i tried to find velocities at each point using :
h+(v^2/2g)=constant
9+v1^2/2g = 6.5+v2^2/2g
and i got to v1-v2=7m/s, wasnt sure what to do from there, so i tried a different method...
I assumed the critical depth would be 6.5, Emin=1.5hc given Emin=9.75
I then subbed that into the equation E=h+(v^2/2g) to give v=7.99m/s
i then subbed into eq v=q/h to give q=51.935
then Q=qB
= 51.935 x 20
=1038.7 m^3/s
however answer is
832.52 m^3
/s
any help would be appreciated. Thanks
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