Flux: Surface integral of a sphere.

In summary, the problem involves finding the surface integral of \vec{r} over a sphere of radius a and the volume integral of \nabla \bullet \vec{r}. Using the Divergence theorem, the volume integral is calculated to be 3 times the volume of the sphere, or 4\pir^{3}. However, for the surface integral, the unit outward normal can be simplified to \hat{n} = \frac{\vec{r}}{|\vec{r}|} and evaluated on the surface of the sphere. This can be done more easily in spherical coordinates, leading to a simplified solution.
  • #1
Kizaru
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Homework Statement


Find the surface integral of [tex]\vec{r}[/tex] over a surface of a sphere of radius a and center at the origin. Also find the volume integral of [tex]\nabla[/tex] [tex]\bullet[/tex] [tex]\vec{r}[/tex].

Homework Equations


Divergence theorem.

The Attempt at a Solution


First I did the volume integral part of the divergence theorem. I obtained [tex]\nabla[/tex] [tex]\bullet[/tex] [tex]\vec{r}[/tex] = 1 + 1 + 1 = 3. So I figured, the answer must be 3*volume = 4[tex]\pi[/tex]r[tex]^{3}[/tex] (I don't know why the pi looks like an exponent, but it's 4 pi r^3)

This answer seems like a correct one.

Now the surface integral I'm having trouble with. Knowing that the equation of the sphere is
x[tex]^{2}[/tex]+y[tex]^{2}[/tex]+z[tex]^{2}[/tex]=a[tex]^{2}[/tex], I found [tex]\nabla[/tex] [tex]\bullet[/tex] (x[tex]^{2}[/tex]+y[tex]^{2}[/tex]+z[tex]^{2}[/tex]) to obtain the normal. The [tex]\vec{r}[/tex] [tex]\bullet[/tex] [tex]\vec{n}[/tex] = 2x[tex]^{2}[/tex] + 2y[tex]^{2}[/tex] + 2z[tex]^{2}[/tex].

So I would integrate this over the surface in Cartesian coordinates, or convert to spherical and integrate? Is the normal suppose to be the normal unit vector? I appear to be obtaining the wrong answer no matter which way I am doing this. What exactly would the integral in cartesian coordinates contain for boundaries?

Thanks. Sorry if the latex syntax is not perfect.
 
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  • #2
For the first integral your answer should be 4 pi a^3, not 4 pi r^3.

You probably aren't asked to find "the surface integral of [tex]\vec{r}[/tex] over a surface of a sphere". I'm guessing you are asked to find the flux integral for the vector field [tex]\vec{r}[/tex]. In other words you are to calculate

[tex]\int\int_S \vec r \cdot \hat n\, dS[/tex]

where [tex]\hat n[/tex] is the unit outward normal. In the case of your sphere your unit outward normal is:

[tex] \hat n = \frac {\vec r}{|\vec r |}[/tex]

Now the natural way to do such an integral would be spherical coordinates. But when you evaluate [tex] \vec r \cdot \hat n[/tex] on the surface of the sphere you should see a shortcut.
 
  • #3
Thanks!
 

FAQ: Flux: Surface integral of a sphere.

What is flux?

Flux is a measure of the flow of a physical quantity through a surface. It is represented by the symbol Φ and is defined as the surface integral of a vector field over a given surface.

What is a surface integral?

A surface integral is a mathematical tool used to calculate the net flow of a vector field through a given surface. It involves evaluating the vector field at each point on the surface and then summing up those values over the entire surface.

What is a sphere?

A sphere is a three-dimensional geometric shape that is perfectly round and has all points on its surface equidistant from its center. It can be thought of as a three-dimensional version of a circle.

How is the surface integral of a sphere calculated?

The surface integral of a sphere can be calculated by first choosing a coordinate system, such as spherical coordinates, to represent the surface of the sphere. Then, the vector field is evaluated at each point on the surface and those values are integrated over the surface using appropriate mathematical techniques.

What is the significance of calculating the surface integral of a sphere?

Calculating the surface integral of a sphere can provide important information about the flow of a vector field through a spherical surface. This can have practical applications in fields such as physics, engineering, and fluid dynamics.

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