Force and change in momentum with time

In summary, the conversation discusses two physics problems involving forces, momentum, and velocity. The first problem involves calculating the changes in momentum and velocity of a 3.00-kg object when a constant force of 6.00N is applied for 10.0 seconds. The second problem involves finding the resulting change in momentum and the magnitude of the external force when a 625-kg car's velocity changes from 10.0 m/s to 44.0 m/s in 68.0 seconds. The conversation also touches on the equations for momentum and the impulse an object experiences, and the importance of using units in calculations. Finally, the participants come to a solution by using the equation F=\frac{dp}{dt}.
  • #1
chowyo123
12
0
Hey, It's been about 2 weeks since I've had a physics class and I just can't seem to put things together again.
I have two problems that seem like they should be easy, and I'm sure they are, but am unsure on how to do them.

A constant force of 6.00N acts on a 3.00-kg object for 10.0 s. What are the changes in the objects momentum and velocity?

I have the equation momentum p = mv. p=(F)(delta t). Could I just do 6.00-N x 10=(3.00-kg)v and solve for v to find the velocity?

The second problem is
The velocity of a 625-kg car is changed from 10.0 m/s to 44.0 m/s in 68.0 s by an external constant force. What is the resulting change in momentum of the car? What is the magnitude of the force?
I tried to do p=(625)(44-10.0) to find the momentum, but that does not seem right to me. What do i do?
 
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  • #2
For question one I don't think your looking for a velocity, your're looking for a change in velocity.
 
  • #3
(delta p) = F (delta t) ... there has to be a change on both sides !

or only one side, with a ratio on the other side : F = (delta p) / (delta t).

or nowhere, as in : p = m v .

now, in your (625)(44 - 10) , does the other side have a delta, or not?

and whatever happened to UNITS ?!
 
  • #4
The impulse that an object experiences is equal to the change in it's momentum!
 
  • #5
Alright, I ended up remembering how to do these problems.
 
  • #6
Yeah, just remember that [tex]F=ma[/tex] only works at low velocities, but [tex]F=\frac{dp}{dt}[/tex] is true always.
 

FAQ: Force and change in momentum with time

What is momentum?

Momentum is a measurement of an object's motion and is defined as the product of its mass and velocity. In other words, it is the quantity of motion an object has.

How does force affect momentum?

According to Newton's second law of motion, force is directly proportional to the rate of change of momentum. This means that the stronger the force applied to an object, the greater the change in its momentum will be.

Can momentum be conserved?

Yes, momentum is a conserved quantity, meaning it can neither be created nor destroyed. In a closed system, the total momentum before and after an interaction will be the same. This is known as the law of conservation of momentum.

What is impulse?

Impulse is the change in an object's momentum. It is equal to the force applied to the object multiplied by the time interval over which the force acts. In other words, it is the area under a force vs. time graph.

How is momentum related to acceleration?

Momentum is directly proportional to acceleration. This means that the greater the momentum of an object, the greater its acceleration will be for a given force. In fact, the rate of change of momentum is equal to the net force acting on the object.

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