- #1
Paras Lehana
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Hi physicists here. :)
I've just joined the forums and here's my very first question :P :
Aakash PHYSICS JEE (Main & Advanced) Study Package - 5 & 6 (Class XII)
Chapter - Electric Charges and Field
Assignment (page 12)
SECTION - A; Q.no - 1
What I expected the answer to be was (1). The electric field due to a conducting sphere of charge Q is equivalent to the same due to a point charge at the center of the sphere as total charge on it appears as concentrated at the center for the points outside the charged sphere. So, the force should have remained the same.
Any suggestions?
Well, it's really nice meeting you all. :)
P.S.: I didn't think it to be a homework question. Well, if moderator thinks it is, the same can move the thread. I beg your pardon for that on the grounds that I just joined the joined the forum today.
I've just joined the forums and here's my very first question :P :
Aakash PHYSICS JEE (Main & Advanced) Study Package - 5 & 6 (Class XII)
Chapter - Electric Charges and Field
Assignment (page 12)
SECTION - A; Q.no - 1
The force of repulsion between two point charges is F, when they are d distance apart. If the point charges are replaced by conducting spheres each of radius r and the charge remains same. The separation between the center of sphere is d, then force of repulsion between them is
(1) Equal to F
(2) Less than F
(3) Greater than F
(4) Cannot be said
Answer - (2) Less than F
What I expected the answer to be was (1). The electric field due to a conducting sphere of charge Q is equivalent to the same due to a point charge at the center of the sphere as total charge on it appears as concentrated at the center for the points outside the charged sphere. So, the force should have remained the same.
Any suggestions?
Well, it's really nice meeting you all. :)
P.S.: I didn't think it to be a homework question. Well, if moderator thinks it is, the same can move the thread. I beg your pardon for that on the grounds that I just joined the joined the forum today.
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